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olya-2409 [2.1K]
2 years ago
11

Suppose a car going 65 mph is traveling north parallel to a train going 50 mph. Once the front of the car is as far north as the

back of the train it takes another three minutes for the front of the car to be further north than the front of the train. How long is the train?​
Mathematics
1 answer:
scoray [572]2 years ago
6 0

Answer:

0.75 Miles

Step-by-step explanation:

To find the answer we have to find the difference in the distance the train and car travelled

65/60 is 1.083333 which is miles per minute then multiplied by 3 is 3.25 mile gone in 3 minutes

For the train it is 50/60 which is 0.833333 and the times 3 is 2.5 miles in three minutes

3.25 miles minus 2.5 miles is 0.75 miles so that is how long the train is

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Please help 10 points to the one who answers correctly and tells me how to solve it.
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3 years ago
The table can be used to determine the solution of equations, 2x − 2y = 6 and 4x + 4y = 28. A table with 6 columns and 2 rows. T
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The solution is (5,2)

Step-by-step explanation:

From the third column the equation for sum of equivalent system is given as;

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divide both sides by 8 to get value of x

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Using the value of x in the fifth column's first equation will be;

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Solving simultaneous equations : brainly.com/question/12647791

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