Let the three items be M, Y and P.
n{M ∩ Y} only = 4-3 = 1
n{M ∩ P) only = 5-3 = 2
n{ Y ∩ P} only = 2
n{M} only = 12-(1+3+2) = 6
n{Y} only = 10-(1+2+3) = 4
n{P} only = 14-(2+3+2) = 7
n{M∩P∩Y} = 3
Number of women in the group = 6+4+7+(1+2+2+3) as above =25 women.
{x+2y+2z=0
{2x+y+z=3
{x-3y-z=1
{x+2y+2z=0
-
{4x+2y+2z=6
{-3x=-6 → x=2
{-3y-z=-1
+
{y+z=-1
{-2y=-2 → y=1
{2+2+2z=0 → 2z=-4 → z=-2
Final triple is
(2; 1; -2)
Answer:
z = 11
Explanation:
5y + 13 = 6y
Subtract 5y by both sides.
13 = y
Next,
z + 22 = 3z
Subtract z by both sides.
22 = 2z
Then, divide both sides by 2.
11 = z
Finally plug those answers into the equations.
5(13) + 13 = 78
6(13) = 78
(11) + 22 = 33
3(11) = 33
So △DEF ≅ △JKI because the value of z = 11.
Answer:3
Step-by-step explanation:
