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Lana71 [14]
3 years ago
13

What is 10^-10 in decimal form?

Mathematics
1 answer:
S_A_V [24]3 years ago
6 0
10^-10 in decimal form is 0.000000001. Because the exponent is negative, you move the decimal point ( decimal point is at the end of 0 of the base number 10) 10 place to the right of 10 and u get the answer above. I discarded the 0 later in the answer because now that you've moved the decimal, that 0 have no value. But when forming it in decimal you have to use that 0 or you will get a wrong answer, instead of eight 0's, you will end up with nine 0's.
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PLZ ANSWER THIS<br> thanksssss
just olya [345]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Terry is skiing down a steep hill. Terry's elevation, E(t), in feet after t seconds is given by E(t)=2600−50t.
lesya692 [45]

Answer:

Part 1) The equation tells us that Terry started at an elevation of 2,600 ft

Part 2) The elevation is decreasing by 50 feet each second

Step-by-step explanation:

we have

E(t)=2,600-50t

where

E(t) is Terry's elevation in feet

t is the time in seconds

Part 1) Find the E intercept of the equation

The E-intercept is the value of E when the value of t is equal to zero

so

For t=0

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E(0)=2,600\ ft

therefore

The equation tells us that Terry started at an elevation of 2,600 ft

Part 2) Find the slope of the equation

we have

E(t)=2,600-50t

This is the equation of the line into slope intercept form

The slope m is equal to

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The slope is negative, because is decreasing

therefore

The elevation is decreasing by 50 feet each second

6 0
3 years ago
What is the result when the following code is run? double x = 1; double y = 1; int i = 0; do { y = x / 2; x = x + y; i = i + 1;
Mama L [17]

Answer:

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Step-by-step explanation:

1. At the begining of the program we start by declairing the variables:

 double x=1, double y=1 and int i=0.

2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.

y=x/2 is the first calculation

x=x+y is the second one. Here is where the values of the variable x changes.

a) for the first iteration, the values of y and x are shown below:

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The variable x is minor to 2.5 so the loop will continue computing.

b)   the second iteration, the values of y and x are shown below::

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The variable x is still minor to 2.5 so the loop will continue computing.

c) third iteration:

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The condition x<2.5 is not true so the loop ends.

3. System.out.print(i + " "); displays the value of the variable i wich value is 3.

Therefore the number 3 is display.

6 0
3 years ago
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Answer

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2 years ago
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