All categories

3 years ago

B. 6 – (−3) 2 + 6 ÷ (-3)

Mathematics

1 answer:

Kipish [7]3 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

Pls can someone help me and have it right

dangina [55]

Answer:

Problem 1:

a. x=2

b. x=3

c. x=1

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Step-by-step explanation:

Given in problem 1:

(a). The equation is $\frac{x}{6} > 1$

It holds true for all values of $x> 6$ .

Let us say $x=12$ ,

$\frac{x}{6}=\frac{12}{6} =2$ which is greater than 1.

(b). The equation is $\frac{x}{6} < 1$

It holds true for all values of $x< 6$ .

Let us say $x=3$

$\frac{x}{6} =\frac{3}{6} =\frac{1}{2}$ which is less than 1.

(c). The equation is $\frac{x}{6} = 1$

It holds true for only $x= 6$ .

Let us say $x=6$ ,

$\frac{x}{6} =\frac{6}{6}=1$ which is equal to 1.

Problem 2:

A multiplication equation to hold the table true:

$18\times3=54$

A division equation to hold the table true:

$\frac{54}{3} =18$

Therefore these are the values which hold true to the equation in problem 1 and 2.

8 0

3 years ago

I put this into my calculator but it keeps coming out as "error" :/ not sure if it's just my calculator or something with the pr

Triss [41]

Your calculator says error because you cant have a square root of a negative number because there is no solution to that maybe recheck your equation and try again

8 0

3 years ago

What’s the volume will give brainliest

grigory [225]

I dont know but thanks for your points

6 0

3 years ago

Read 2 more answers

356 I want the greatest odd number by using these num

kari74 [83]

Answer:

Step-by-step explanation:

We cant make greatest odd num by adding these numbers but:

3 0

3 years ago

Solve on the interval [0/2pi]<br><br> 1-cos(theta) = (1/2)

Airida [17]

Answer:

Final answer is $x=\frac{\pi}{3}$ and $x=\frac{5\pi}{3}$ .

Step-by-step explanation:

Given equation is $1-\cos\left(\theta\right)=\frac{1}{2}$

Now we need to find the solution of $1-\cos\left(\theta\right)=\frac{1}{2}$ in given interval $[0, 2\pi ]$ .

$1-\cos\left(\theta\right)=\frac{1}{2}$

$-\cos\left(\theta\right)=\frac{1}{2}-1$

$-\cos\left(\theta\right)=-\frac{1}{2}$

$\cos\left(\theta\right)=\frac{1}{2}$

which gives $x=\frac{\pi}{3}$ and $x=\frac{5\pi}{3}$ in the given interval.

Hence final answer is $x=\frac{\pi}{3}$ and $x=\frac{5\pi}{3}$ .

6 0

3 years ago