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kirza4 [7]
3 years ago
6

Help please:)10 points​

Mathematics
1 answer:
melamori03 [73]3 years ago
6 0

Answer:

vbrainiest?

Step-by-step explanation:

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Line q passes through points (9, 9) and (1, 2). Line r is perpendicular to q. What is the slope of line r?
Alik [6]

Answer:

y=mx+b

Step-by-step explanation:

6 0
3 years ago
To reduce laboratory​ costs, water samples from five public swimming pools are combined for one test for the presence of bacteri
aleksklad [387]

Answer:

Step-by-step explanation:

Given that:

The numbers of the possible public swimming pools are 5

From past results, we have 0.007 probability of finding bacteria in a public swimming area.

In the public swimming pool, the probability of not finding bacteria = 1 - 0.007

= 0.993

Thus;

Probability of combined   =  Probability that at least one public

sample with bacteria           swimming area have bacteria

Probability of combined sample with bacteria  = 1 - P(none out of 5 has          

                                                                                bacteria)

   

Probability of combined sample with bacteria = 1 - (0.993)⁵        

= 1 - 0.9655

= 0.0345

Thus, the probability that the combined sample from five public swimming areas will show the presence of bacteria is 0.0345

From above, the probability that the combined sample shows the presence of bacteria is 0.0345 which is lesser than 0.05.

Thus, we can conclude that;  Yes, the probability is low enough that there is a need for further testing.

6 0
3 years ago
Adelaide paid $35 for a manicure and gave the manicurist a 20% tip.
Nikolay [14]
That would be 35 + 0.20*35  =  $42
7 0
3 years ago
What is the exact value of cos (67.5°)?
babymother [125]

first off, make sure you have a Unit Circle, if you don't do get one, you'll need it, you can find many online.

let's double up 67.5°, that way we can use the half-angle identity for the cosine of it, so hmmm twice 67.5 is simply 135°, keeping in mind that 135° is really 90° + 45°, and that whilst 135° is on the 2nd Quadrant and its cosine is negative 67.5° is on the 1st Quadrant where cosine is positive, so

cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta) \\\\\\ cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos(135^o)\implies cos(90^o+45^o)\implies cos(90^o)cos(45^o)~~ - ~~sin(90^o)sin(45^o) \\\\\\ \left( 0 \right)\left( \cfrac{\sqrt{2}}{2} \right)~~ - ~~\left( 1\right)\left( \cfrac{\sqrt{2}}{2} \right)\implies -\cfrac{\sqrt{2}}{2} \\\\[-0.35em] ~\dotfill

cos(67.5^o)\implies cos\left( \frac{135^o}{2} \right)\implies \pm \sqrt{\cfrac{ ~~ 1-\frac{\sqrt{2} ~~ }{2}}{2}}\implies \stackrel{I~Quadrant}{+\sqrt{\cfrac{ ~~ 1-\frac{\sqrt{2} ~~ }{2}}{2}}} \\\\\\ \sqrt{\cfrac{ ~~ \frac{2-\sqrt{2}}{2} ~~ }{2}}\implies \sqrt{\cfrac{2-\sqrt{2}}{4}}\implies \cfrac{\sqrt{2-\sqrt{2}}}{\sqrt{4}}\implies \cfrac{\sqrt{2-\sqrt{2}}}{2}

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20%20%2B%20%20%5Cfrac%7B7%7D%7B15%7D%20" id="TexFormula1" title=" \fr
luda_lava [24]

Answer:

Step-by-step explanation:

\frac{5}{15}  + \frac{7}{15y}  = \frac{12}{15}  = \frac{4}{5}

6 0
3 years ago
Read 2 more answers
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