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Serhud [2]
3 years ago
13

A random survey of seventh and eighth grade students was conducted to find out how many hours are spent doing homework each nigh

t. Of the two sets of data, which has the greater median?
A: seventh graders
B: eighth graders
C: they have the same median
D: impossible to determine from the box plot

Mathematics
1 answer:
sammy [17]3 years ago
4 0
Eight graders is the answer
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If every 7 minutes I get 10.64k dollars how long will it take for me to get 4.5 million dollars
Ipatiy [6.2K]

Answer:

approx 2960.53 minutes

Step-by-step explanation:

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2 years ago
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Graph the line that passes through the given point and has the given slope m!
Veseljchak [2.6K]

Answer:

The line would be y = -1/4x + 27/4

Step-by-step explanation:

In order to find this, we first need to note that the original slope is -1/4. And since parallel lines have the same slope, we know our new line will have that same slope. Now, we can use that slope and the point in point-slope form and solve for y.

y - y1 = m(x - x1)

y - 6 = -1/4(x - 3)

y - 6 = -1/4x + 3/4

y = -1/4x + 27/4

7 0
3 years ago
The gardener comes four times each month. Each month, Katrina writes a check, and $85.40 is deducted from her bank balance to pa
Natasha_Volkova [10]

Answer:

234.85

Step-by-step explanation:

4 days earning = $85.40

so, 1 day earning will be = $85.40/4 = $21.35

Now, 11 days earning would be: $21.35 * 11 = $234.85

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What is the product of a fraction multiplied by its multiplicative inverse? Justify your answer with an example
Lina20 [59]
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Heres an example: 5/8 • 8/5 = 1
8 0
2 years ago
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
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