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Serhud [2]
3 years ago
13

A random survey of seventh and eighth grade students was conducted to find out how many hours are spent doing homework each nigh

t. Of the two sets of data, which has the greater median?
A: seventh graders
B: eighth graders
C: they have the same median
D: impossible to determine from the box plot

Mathematics
1 answer:
sammy [17]3 years ago
4 0
Eight graders is the answer
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Step-by-step explanation:

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Classify each pair of numbered angles. Drag and drop the descriptions into the boxes to correctly classify each pair of numbered
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(i) Pairs of <em>neighboring</em> angles are <em>supplementary</em> and <em>opposite</em> angles have the <em>same</em> measure.

(ii) The two angles formed by a line coming out of another line are <em>supplementary</em>.

<h3>How to analyze pairs of angles</h3>

(i) When two <em>straight</em> lines pass through each other, then <em>two</em> pairs of <em>opposite</em> angles are constructed. A pair with angles of (3\cdot x + 52)^{\circ} and another pair with angles of (2\cdot x + 2)^{\circ}, each pair of angles with <em>different </em>measures are <em>supplementary</em>.\blacksquare

(ii) When a <em>straight</em> line comes out of another <em>straight</em> line, from a point distinct to any endpoint of the former, then we construct two <em>supplementary</em> angles. The <em>largest</em> angle has a value of (10\cdot x + 20)^{\circ}, whereas the <em>smaller</em> one has a value of (6\cdot x + 8)^{\circ}. \blacksquare

To learn more on angles, we kindly invite to check this verified question:  brainly.com/question/15767203

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3 years ago
Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an
ziro4ka [17]

Answer:

1) is not possible

2) P(A∪B) = 0.7

3) 1- P(A∪B) =0.3

4) a) C=A∩B' and P(C)= 0.3

b)  P(D)= 0.4

Step-by-step explanation:

1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4  . Thus the maximum possible value of P(A∩B) is 0.4

2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by

P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7

P(A∪B) = 0.7

3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3

4) the event C that the selected student has a visa card but not a MasterCard is given by  C=A∩B'  , where B' is the complement of B. Then

P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3

the probability for the event D=a student has exactly one of the cards is

P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4

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I believe the answer is D
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