Answer:
Step-by-step explanation:
try 3 2/3 cups
(i) Pairs of <em>neighboring</em> angles are <em>supplementary</em> and <em>opposite</em> angles have the <em>same</em> measure.
(ii) The two angles formed by a line coming out of another line are <em>supplementary</em>.
<h3>
How to analyze pairs of angles</h3>
(i) When two <em>straight</em> lines pass through each other, then <em>two</em> pairs of <em>opposite</em> angles are constructed. A pair with angles of
and another pair with angles of
, each pair of angles with <em>different </em>measures are <em>supplementary</em>.
(ii) When a <em>straight</em> line comes out of another <em>straight</em> line, from a point distinct to any endpoint of the former, then we construct two <em>supplementary</em> angles. The <em>largest</em> angle has a value of
, whereas the <em>smaller</em> one has a value of
. 
To learn more on angles, we kindly invite to check this verified question: brainly.com/question/15767203
Add 5
5,10,15,20,25,30....
Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
I believe the answer is D