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3 years ago

13

HELP PLEASEEEE!!! First correct answer gets brainliest!

1 answer:

Svetlanka [38]3 years ago

3 0

The answer to the question

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Help me please!!!!!!!!!!!!

mixas84 [53]

Answer:

the measure of angle m`is 120

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2 years ago

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(please answer) <br> If f(x) = (x + 3) - 2, which of the following is the value of f(-3)?

ValentinkaMS [17]

Answer:

f(3)= 4

Step-by-step explanation:

x= -3=0

x= 3

f(3)=(3+3)-2

f(3)= 6-2

f(3)= 4

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3 years ago

Please help me solve problem 8

mixas84 [53]

The answer is A because when a question asks how much is left it typically means that you will need to subtract.

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4 years ago

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Please simplify, 50 points.

olga55 [171]

Answer:

The trigonometric equation (sin Θ − cos Θ)^2 − (sin Θ + cos Θ)^3 can be simplified by:Using x for Θ: (sinx - cosx)^2 - (sinx + cosx)^2 = (sin^2 x - 2sinxcosx + cos^2 x) - (sin^2 x + 2sinxcosx + cos^2 x) = - 2 sinx cosx - 2 sinx cosx = - 4 sinx cosx = - 2sin(2x)

Step-by-step explanation:

4 0

3 years ago

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Find tan2θ if θ terminates in Quadrant IV and cosθ = 3/5.

natali 33 [55]

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$\cos( \alpha ) = \frac{3}{5} \\$

${sin}^{2}( \alpha ) = 1 - {cos}^{2} ( \alpha )$

${sin}^{2}( \alpha ) = 1 - ({ \frac{3}{5} })^{2} \\$

${sin}^{2}( \alpha ) = 1 - \frac{9}{25} \\$

${sin}^{2}( \alpha ) = \frac{25}{25} - \frac{9}{25} \\$

${sin}^{2}( \alpha ) = \frac{16}{25} \\$

$sin( \alpha )= ± \sqrt{ \frac{16}{25} } \\$

In Quadrant IV , sin is negative .

Thus ;

$sin( \alpha ) = - \sqrt{ \frac{16}{25} } \\$

$\sin( \alpha ) = - \frac{4}{5} \\$

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$\tan(2 \alpha ) = \frac{ \sin(2 \alpha ) }{ \cos(2 \alpha ) } \\$

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$\sin(2 \alpha ) = 2. \sin( \alpha ). \cos( \alpha )$

$\sin(2 \alpha ) = 2 \times ( - \frac{4}{5} ) \times ( \frac{3}{5} ) \\$

$\sin(2 \alpha ) = - \frac{24}{25} \\$

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$\cos(2 \alpha ) = {cos}^{2}( \alpha ) - {sin}^{2}( \alpha )$

$\cos(2 \alpha ) = ({ \frac{3}{5} })^{2} - ({ - \frac{4}{5} })^{2} \\$

$\cos(2 \alpha ) = \frac{9}{25} - \frac{16}{25} \\$

$\cos(2 \alpha ) = - \frac{7}{25} \\$

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$\tan(2 \alpha ) = \frac{ \sin(2 \alpha ) }{ \cos(2 \alpha ) } \\$

$\tan(2 \alpha ) = \frac{ - \frac{24}{25} }{ - \frac{7}{25} } \\$

$\tan(2 \alpha ) = - \frac{24}{25} \div - \frac{7}{25} \\$

$\tan(2 \alpha ) = - \frac{24}{25} \times - \frac{25}{7} \\$

$\tan(2 \alpha ) = \frac{24}{7} \\$

Thus the correct answer is (( C )) .

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4 0

3 years ago

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