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bogdanovich [222]
3 years ago
10

Please simplify, 50 points.

Mathematics
2 answers:
olga55 [171]3 years ago
4 0

Answer:

The trigonometric equation  (sin Θ − cos Θ)^2 − (sin Θ + cos Θ)^3 can be simplified by:Using x for Θ: (sinx - cosx)^2 - (sinx + cosx)^2 = (sin^2 x - 2sinxcosx + cos^2 x) - (sin^2 x + 2sinxcosx + cos^2 x) = - 2 sinx cosx - 2 sinx cosx = - 4 sinx cosx = - 2sin(2x)

Step-by-step explanation:

Lady_Fox [76]3 years ago
3 0

Answer:

D

Step-by-step explanation:

Expand (sinΘ + cosΘ)²

= sinΘ - cosΘ - (sin²Θ + 2 sinΘcosΘ + cos²Θ)

= sinΘ - cosΘ - sin²Θ - 2sinΘcosΘ - cos²Θ

= sinΘ - cosΘ - 2sinΘcosΘ - (sin²Θ + cos²Θ)

= - 2sinΘcosΘ - cosΘ + sinΘ - 1 → D

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Answer:

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Step-by-step explanation:

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Which expression is equivalent to 4 sqrt 16x^11y^8/ 81x^7y^6 Assume x> 0 and y=0
Romashka [77]

One interpretation of your intent would be as follows:


                 16x^11y^8

Find 4 √ [-----------------]. Is that what you meant?

                   81x^7y^6

                                                                4*x^5*√x*y^4

If so, then the correct result would be 4 ---------------------

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and this could be reduced to:


       4*x^5 * y^4 * √(x)     4*x^2*y

4 --------------------------- = -------------

      9*x^3*y^3 √(x)               9

8 0
3 years ago
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Do this for me and I will give 42 points, it is 9th grade prob and stats.
Hitman42 [59]

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6 0
3 years ago
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Lostsunrise [7]

Answer:

1-a

2-a

3-b

Step-by-step explanation:

hope that helps

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nirvana33 [79]

Part A.

The area of a triangle is given by the product of its base and the height relative to that base.

Since these triangles have the same base b and same height h, they have the same area.

Part B.

The area of a rectangle or parallelogram is given by the product of base and height. Since these figures have the same base and height, they have the same area.

Part C.

These figures have different shapes, so we can't affirm that they have the same area.

Part D.

The height shown in the image is not the height relative to side b, therefore we can't affirm that the triangles have the same area.

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