X axis : -t1 cos 60 + t2 cos 60 = 0
t2 cos 60 = t1 cos 60 ; t2 = t1
Y axis : t1 sin 60 + t2 sin 60 - 150 = 0
since t2 = t1
2t1 sin 60 = 150
t1 ( sqrt(3)/2) = 150/2
t1 = 50 [sqrt(3)]
t2 = 50 [sqrt(3)]
t3 = 150 N
hope this helps
Answer:
n= 11 & n = 13 is the answer
20 times 4 will get to 80
Use inverse operations and subtract 3 from 9 which is -12 then divide -12 by 6 which is -2
-9=3+6x
-3 -3
-12=6x
-12/6=6x/6
-2=x
Answer:
<h2>m∠ABD = 20°</h2>
Step-by-step explanation:
If m∠ABC = 40° and BD is the bisector of ∠ABC, then
(1) m∠ABD = m∠DBC
(2) m∠ABC = m∠ABD + m∠DBC
From (1) and (2) we have:
m∠ABC = 2m∠ABD
Therefore
2m∠ABD = 40° <em>divide both sides by 2</em>
m∠ABD = 20°
