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3 years ago

8th Grade Math Homework Thursday, January 28th

1 answer:

5 0

1. -6y
2. 4y+20
3. -6x+6y+4
4. 3x-44
5. •work:
•plug in 4 to the equation
5(2-4)=-10
10-20=-10
-10=-10
•so, yes it is a solution to 5(2-x)
6. •work:
4x+20=0
-20 -20
4x=-20
4x/4=-20/4
x=-5
7. •work:
5x-3=2x-27
-2x -2x
3x-3=-27
+3 +3
3x=-24
3x/3=-24/3
x=-8
8. •work:
6x-8=2x+16
-2x -2x
4x-8=16
+8 +8
4x=24
4x/4=24/4
x=6
9. •work:
12-3x=22+2x
-2x -2x
12-5x=22
-12 -12
-5x=10
-5x/-5=10/-5
x=-2
10. •work:
x+7x-12=-20
8x-12=-20
+12 +12
8x=-8
8x/8=-8/8
x=-1
11.•work:
7x+4-13x=-1+23
-6x+4=-1+23
-6x+4=22
-4 -4
-6x=18
-6x/-6=18/-6
x=3
here you go! hope this helped!! :)

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Which two square roots are used to estimate the square root of 67

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$\bf \boxed{\sqrt{64}}\rule[0.35em]{10em}{0.25pt}\sqrt{67}\rule[0.35em]{19em}{0.25pt}\boxed{\sqrt{81}}$

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2 years ago

A nurse collected data about the average birth weight of babies in the hospital that month. Her data is shown using the dot plot

mixer [17]

Answer:

The values of the box-plot are: B = {8.2, 8.3, 8.4, 8.5 and 8.9}.

Step-by-step explanation:

The data provided is as follows:

X Frequency

8 0

8.1 0

8.2 2

8.3 2

8.4 2

8.5 3

8.6 0

8.7 1

8.8 0

8.9 1

9 0

So, the actual data is:

S = {8.2 , 8.2 , 8.3 , 8.3 , 8.4 , 8.4 , 8.5 , 8.5 , 8.5 , 8.7 , 8.9 }

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

Minimum (shown at the bottom of the chart)
First Quartile (shown by the bottom line of the box)
Median (or the second quartile) (shown as a line in the center of the box)
Third Quartile (shown by the top line of the box)
Maximum (shown at the top of the chart).

The data set is arranged in ascending order.

The minimum value is, Min. = 8.2

The lower quartile is,

$[\frac{n+1}{4}]^{th}\ obs.=[\frac{11+1}{4}]^{th}\ obs.=3^{rd }\ obs. =8.3$ ,

Q₁ = 8.3.

The median value is,

$[\frac{n+1}{2}]^{th}\ obs.=[\frac{11+1}{2}]^{th}\ obs.=6^{th}\ obs.=8.4$

Median = 8.4

The upper quartile is,

$[\frac{3(n+1)}{4}]^{th}\ obs.=[\frac{3(11+1)}{4}]^{th}\ obs.=9^{th }\ obs. =8.5$ ,

Q₃ = 8.5.

The maximum value is, Max. = 8.9.

So, the values of the box-plot are: B = {8.2, 8.3, 8.4, 8.5 and 8.9}.

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3 years ago

There are 3,848 students and staff at happy town high school. if the principal friendly and 15 teachers are infected by a zombie

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Answer:

Step-by-step explanation:

at firth hr - 15×2=

2 nd hr - 60×2

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2 years ago

What is the nth term in the sequence: 4, 7, 12, 19, 28 Please show working out

Anna71 [15]

The correct answer is n²+3.

Explanation:
We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.

Since these are different, this is not linear.

We now find the second differences:
5-3=2; 7-5=2; 9-7=2.

Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².

We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.

Now we find the difference between the actual terms of the sequence and the numbers we just found:

4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.

Since this is constant, the sequence is in the form (1/2a)n²+d;
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