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kolbaska11 [484]
3 years ago
13

A large container holds 8 gallons of water. After 56 minutes the container only has 1 gallon of water left. At what rate is the

water leaking. gal/min​
Mathematics
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

The rate at which water leaking is \frac{1}{8} gal/min.

Step-by-step explanation:

Given:

A large container holds 8 gallons of water.

After 56 minutes the container only has 1 gallon of water left.

Now, to find at what rate is the water leaking.

So, water leaked from the container = 8 gallons - 1 gallon = 7 gallons.

Time taken for leakage = 56 minutes.

<em>Now, to get the rate:</em>

\frac{Gallons\ of\ water\ leaked}{Time\ taken\ for\ leakage}

=\frac{7 gallons}{56 minutes}

=\frac{1 gallon}{8 minutes}

The rate = \frac{1}{8} gal/min.

Therefore, the rate at which water is leaking is \frac{1}{8} gal/min.

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Answer:

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Step-by-step explanation:

The sandbox has a ratio of 2:3. If you plug the numbers in with the ratio, you can find the actual dimensions.

Let x be the length

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3 years ago
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Answer:

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Step-by-step explanation:

Given,

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Since, north and east are perpendicular to each other, so we can write the resultant velocity in vector form as,

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Hence, the magnitude of resultant velocity can be written as

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3 years ago
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