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Sladkaya [172]
3 years ago
6

How many solutions is 8x+47=8(x+5)

Mathematics
2 answers:
expeople1 [14]3 years ago
7 0
8x + 47 = 8x + 40

No solutions  (the above 2 expressions cannot be equal for any value of x)
Morgarella [4.7K]3 years ago
6 0
8x+47=8(x+5)

8x+47=8x+40
8x+47-47=8x+40-47
8x=8x-7
8x-8x=8x-7-8x
0=-7
there is no solutions 
Hope this helps :)
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Which statements about the system are true?
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2 Answers:

  • B)  The lines are parallel
  • C)  The lines have the same slope.

Parallel lines always have equal slope, but different y intercepts.

==========================================================

Explanation:

Let's solve the second equation for y

3y - x = -7

3y = -7+x

3y = x-7

y = (x-7)/3

y = x/3 - 7/3

y = (1/3)x - 7/3

The equation is in y = mx+b form with m = 1/3 as the slope and b = -7/3 as the y intercept. We see that the first equation, where y was already isolated, also has a slope of m = 1/3. The two equations of this system have the same slope. Choice C is one of the answers.

However, they don't have the same y intercept. The first equation has y intercept b = -4, while the second has b = -7/3. This means that they do not represent the same line. They need to have identical slopes, and identical y intercepts (though the slope can be different from the y intercept of course) in order to have identical lines. So we can rule out choice D and E because of this.

Because the two equations have the same slope, but different y intercepts, this means the lines are parallel. Choice B is the other answer.

Parallel lines never touch or intersect, which in turn means there is no solution point. A solution point is where the lines cross. We can rule out choice A.

I recommend using your graphing calculator, Desmos, GeoGebra, or any graphing tool (on your computer or online) to graph each equation given. You should see two parallel lines forming. I used GeoGebra to make the graph shown below.

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Answer:

c. domain: {-2, 0, 2}, range: {-1, 1, 3}

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Given:

There are three points on the graph.

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The points are (-2,-1),(0,1),\textrm{ and }(2,3)

Domain is the set of all possible x values. Here, the x values are -2, 0 and 2.

So, domain is: {-2, 0, 2}.

Range is set of all possible y values. Here, the y values are -1, 1 and 3.

So, range is: {-1, 1, 3}

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A paper cup is a perfect cylinder that is 6.4 cm tall and 3 cm across. Find the total area of paper needed to make the cup, to t
NNADVOKAT [17]

Hey there! I'm happy to help!

We want to find how much paper we need to make the cup. So, we need to find the surface area of the cylinder, which is basically the "walls and floors" of the cup. So, this is the circle on the bottom and the surrounding stuff that goes up. There is no circular top to this cup, which will be important when finding the total area of paper.

So, first we need to find how much paper we need to make the bottom circle. The formula for the area of a circle is A=πr². This r represents the radius, or the distance from the center of the circle to the edge. We are given that the cup is 3 cm completely across, and the radius is be half of that, so the radius is 1.5 cm. Let's find the area. We will use 3.14 for π.

π×1.5²=7.065

Now, we need  to find the area of the walls of the cup. The wall is a rectangle that is basically wrapped around the circle. The height of the rectangle is the height of the cup and the length of the rectangle is the circumference (perimeter) of the bottom circle because the length of the rectangle wraps completely around the circle.

First, let's find the circumference of the circle. The circumference is the diameter (distance across the circle, so 3 cm) multiplied by π. We will use 3.14 for π.

3π=9.42

So, this means that the long side of the rectangle is 9.42 cm, and now we multiply this by the height.

9.42×6.4=60.288

Now, we add the rectangle area and the bottom circle area.

60.288+7.065=67.353

But, they want us to round to the nearest centimetre, so we will just say 67 square centimetres.

An important thing to note is that this is not  the area of a normal cylinder (one with a top and a bottom circle) because it is a cup so it does not have a top. If you have a cylinder with a top and a bottom, you would just multiply the area of the circle by two, so then you have the top and bottom. If that were the case, the area of our cylinder would be 74 cm with the numbers we have been given here.

Have a wonderful day!

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