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Lady bird [3.3K]
2 years ago
9

Which property can be used to expand the expression -2(3/4x +7)

Mathematics
1 answer:
katrin [286]2 years ago
7 0

Answer:

The distributive property

Step-by-step explanation:

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-12.405 as a mixed number in simplest form please
scZoUnD [109]

\\ \ast\sf\longmapsto -12.405

\\ \ast\sf\longmapsto -\dfrac{12405}{1000}

  • Simplify until possible

\\ \ast\sf\longmapsto -\dfrac{2481}{200}

Now

\\ \ast\sf\longmapsto -12\dfrac{81}{200}

7 0
2 years ago
El número equivalente de 25/50 por favor
Viefleur [7K]

Answer:

El número equivalente de 25/50 es 1/2

Step-by-step explanation:

3 0
2 years ago
The following graph shows a bus’s record of the number of passengers it picked up over the course of a day. A bar graph titled B
Setler [38]

Answer:

(A)55

Step-by-step explanation:

\left|\begin{array}{c|ccccccccccccccc}x(Time)&7&8&9&10&11&12&1&2&3&4&5&6\\y(Passsengers)&40&62&58&43&36&55&41&28&31&37&75&64\end{array}\right|

From the values on the graph which is presented in the table above, the number of people who rode the bus during the 12.00 hour is 55.

<u>The correct option is A.</u>

7 0
3 years ago
Read 2 more answers
If a club charges dues of $200 a year, it will have 50 members. For each $5 it raises its dues, it loses a member. USE AN EQUATI
Vikentia [17]

Answer:

The value is      y  =  \$ 225

Step-by-step explanation:

From the question we are told that

   The amount charge per year is  k  =  \$ 200

   The  number of members it will have at this amount is  n  =  50

   The amount amount increase that will lead to the loss of a single member is   z =  \$ 5

        Generally the total amount the club would obtain from  its members is mathematically represented as

      I  =  Amount \  due\ paid *  Number \  of members

Now let x denote the number of member lost

Hence

      I  =  (k + zx) (n-x )

=>    I  =  (200 + 5x) (50-x )

=>  I  = 10000+50x-5x^2

Thus the number of members that be removed to  give the maximum  income from dues is obtained by differentiating the above equation and equating it to zero

           \frac{dI}{dx}  =  50-10x

=>         x   =  5

So from  I  =  (200 + 5x) (50-x ) we have

          I  =  (200 + 5 (5)) (50-5 )

           I  = \$ 10125

So the amount the club should charge is    

         y  =  \frac{10125}{50 - 5}

         y  =  \$ 225

         

7 0
3 years ago
Can someone help me please
ELEN [110]
9. 5y
10.10x^2-1 
not done 
3 0
3 years ago
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