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3 years ago

Does any body know how to do a collaboration component

1 answer:

6 0

I usually don't do collaboration components with like other people, I attend the live sessions to complete the collaboration component which is much easier.. Just check whens the next collab live session for the assesment u need to do.

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Given that |-6| > 5, which statement is not true?

ollegr [7]

I believe the answer is # 4

6 0

3 years ago

Read 2 more answers

5 cakes cost £4 how much do 7 cakes cost

Nostrana [21]

You can solve this using proportion.

5 = 4

7 = ?

7(4)/5= 5.6

7 cakes cost £5.6

4 0

2 years ago

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I need help with the equation.

natulia [17]

Answer:

(x - 3)² + (y + 9)² = 25

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

Given area = 25π , that is

πr² = 25π ( divide both sides by π )

r² = 25 ( take the square root of both sides )

r = $\sqrt{25}$ = 5

With centre (h, k) = (3, - 9 ) and r = 5 , then

(x - 3)² + (y - (- 9) )² = 5² , that is

(x - 3)² + (y + 9)² = 25

8 0

3 years ago

Read 2 more answers

Can someone help me please

Novosadov [1.4K]

Answer:

Substitute the 80°F where the F is in the equation. then just put the whole equation into your calculator. I got approximately 26.7.

4 0

2 years ago

Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology ex

Nataly [62]

Answer:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion female for Biology

$\hat p_A =\frac{84199}{144796}=0.582$ represent the estimated proportion female for biology

$n_A=144796$ is the sample size for A

$p_B$ represent the real population proportion female for calculus AB

$\hat p_B =\frac{102598}{211693}=0.485$ represent the estimated proportion female for Calculus AB

$n_B=211693$ is the sample size required for B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

5 0

3 years ago