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Pavlova-9 [17]
3 years ago
6

use the point-slope equation to identify the slope and the coordinates of a point on the line y – 4 = 1/2 (x – 1). the slope of

the line is . a point on the line is

Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0

Answer:

The slope of the line is \dfrac{1}{2} and a point on the line is (1, 4)  

Step-by-step explanation:

The general point slope of line passing through (x_1,y_1) and having slope as m.

y-y_1=m(x-x_1)

The given equation of the straight line,

y-4=\dfrac{1}{2}(x-1)

Comparing this to the general equation we get the point as (1, 4) and slope as \dfrac{1}{2}

Elden [556K]3 years ago
7 0

we know that

The equation of the line into point-slope form is equal to

y-y1=m(x-x1)

where

m is the slope

(x1,y1) is the point

In this problem we have

y-4=\frac{1}{2}(x-1)

therefore

<u>The slope is equal to</u>

m=\frac{1}{2}

<u>The point is equal to</u>

(1,4)

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Who knows the answer for this question
Vadim26 [7]

Answer: 7

Work: So, the goal is to get z alone, so we are going to add 85 on both sides, cancelling on the side it's currently on. So, the new equation is going to be 25z = 175. Then, to get z even more lonely, we are going to divide 25 on both sides, and again cancelling it on the side it's currently on. So, the answer is z = 7. I hope this helps, and Happy Holidays! :)

8 0
2 years ago
Read 2 more answers
What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?
andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5)  and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)  

To Find:

M(x₄ ,y₄) = ?  and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

As M is the mid point of PR and N is the mid point of RQ so we will have

Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})

Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})

Substituting the given value in above equation we get

Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)

Similarly,

Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)

∴ M(x₄ ,y₄) = (-3.5 , 0.5)  and

  N (x₅ ,y₅) = ( -1 , -0.5 )

3 0
3 years ago
The width of a rectangle is 4 1/6 feet, and its area is 35 square feet. What is the perimeter of this rectangle?
DanielleElmas [232]

Answer:

perimeter = 25.13feets

Step-by-step explanation:

width = 25/6 feet

Area = 35 square feet

lenght = Area/width = (35*6)/25 = 8.4feets

perimeter of the rectangle = 2(25/6 + 8.4) = 25.13 feets

5 0
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Which is a needed step to prove that AABF = AEDG?
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Step-by-step explanation:

7 0
3 years ago
the sum of two numbers is 70. the larger number is five less than twice the smaller number . what are the two numbers
earnstyle [38]
X+y=70
x=2y-5
x=larger number
y=smaller number
now plug in the value of x to only have one variable in the equation...
Way to solve for y:
(2y-5)+y=70
3y-5=70
add 5 on both sides...
3y=75
divide by 3 on both sides
y=25
1st way to solve for x:
now plug in y in the original equation...
x+25=70
subtract 25 on both sides...
x=45
2nd way to solve for x:
plug in y for the second equation...
x=25(2)-5
x=50-5
x=45
answer: the two numbers are 45 and 25.

3 0
3 years ago
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