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Deffense [45]
3 years ago
9

A tower casts a shadow that is 60 feet long when the angle of elevation of the sun is 65˚. how tall is the tower?

Mathematics
2 answers:
Mila [183]3 years ago
8 0

Answer:

70 ft i think

Step-by-step explanation:

Kay [80]3 years ago
7 0

Answer:

128.67 ft

Step-by-step explanation:

Topic: Trigonometric Functions

You should be familiar with the concept of trigonometric functions because this topic involves degrees of traingles with the lenght of their sides, as you can see in the image, you need to remember which trigonometric function involves both sides (not hypotenuse) of a triangle, let's review

O= opposite, A = adjacent, H = Hypotenuse, α = 65°

sen (α) = \frac{O}{H}

cos(α) = \frac{A}{H}

tan(α) = \frac{O}{A}

guess which of them works? yeah its tan(α), so we have that

tan(65°) = \frac{h}{60 ft}

findig h in the previous equation we have that

60 ft * tan(65°) = h

computing in a calculator it means that the height (h) of the tower is

h = 128. 67 ft

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70 POINTS!!!!!!!!!! Given: E, F, Q, D∈k(O),O ∈ ED, m∠DFQ = 10°, measure of arc EF = 28° Find: Angles of △EFQ
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Answer:

The measures of angles of triangle EFQ are

1) m\angle EFQ=100\°

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3) m\angle EQF=14\°

Step-by-step explanation:

step 1

Find the measure of arc QD

we know that

The inscribed angle is half that of the arc it comprises.

m\angle DFQ=\frac{1}{2}(arc\ QD)

substitute the given value

10\°=\frac{1}{2}(arc\ QD)

20\°=(arc\ QD)

arc\ QD=20\°

step 2

Find the measure of arc FQ

we know that

arc\ QD+arc\ FQ+arc\ EF=180\° ---> because ED is a diameter (the diameter divide the circle into two equal parts)

substitute the given values

20\°+arc\ FQ+28\°=180\°

arc\ FQ=180\°-48\°=132\°

step 3

Find the measure of angle EFQ

we know that

The inscribed angle is half that of the arc it comprises.

m\angle EFQ=\frac{1}{2}(arc\ QD+arc\ ED)

substitute the given value

m\angle EFQ=\frac{1}{2}(20\°+180\°)=100\°

step 4

Find the measure of angle FEQ

we know that

The inscribed angle is half that of the arc it comprises.

m\angle FEQ=\frac{1}{2}(arc\ FQ)

substitute the given value

m\angle FEQ=\frac{1}{2}(132\°)=66\°

step 5

Find the measure of angle EQF

we know that

The inscribed angle is half that of the arc it comprises.

m\angle EQF=\frac{1}{2}(arc\ EF)

substitute the given value

m\angle EQF=\frac{1}{2}(28\°)=14\°

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