Answer:
141
Step-by-step explanation:
We need to first find the volume of the cannonballs and then, divide the volume of the closet by the volume of the cannonballs.
The radius of the spherical cannonball is 0.75 feet.
The volume of a sphere is:
where r = radius
Therefore, the volume of the cannonballs is:
Therefore, the number of cannonballs that can fit the closet is:
250 / 1.77 = 141.24
Since the number is a maximum and it must be a whole number, the number of cannonballs that can fit the closet is 141.
Take the logarithm of both sides and expand the right hand side:
Now take the derivative of both sides with respect to :
I'd stop there, but you could condense the right side a bit to get
Answer:
Step-by-step explanation:
we know that
For every 1000-m increase in altitude, the pressure decreases about 11.9%
so
at an altitude of 2000 m, the pressure decreases about 2*11.9%=23.8%
therefore
Answer:
(B)
Step-by-step explanation:
Volume of fluid in the tank =1000 gallons
Initial Amount of Salt in the tank, A(0)= 30 pounds
Incoming brine solution of concentration 2 pounds of salt per gallon is pumped in at a rate of 4 gallons per minute.
Rate In=(concentration of salt in inflow)(input rate of brine)
The resulting mixture is pumped out at the same rate, therefore:
Rate Out =(concentration of salt in outflow)(output rate of brine)
Therefore:
The rate of change of amount of salt in the tank,
Answer:
-intercept is
-intercept is
Step-by-step explanation:
Let denotes time denoted (in minutes) by a person in jogging.
Let denotes time denoted (in minutes) by a person in running.
A person is wanting to burn 500 calories a day through exercise. They know that they burn 7.3 calories a minute jogging and 11.3 calories a minute running.
So, equation becomes
For -intercept, put
So, -intercept is
For -intercept, put
So, -intercept is
Differentiate equation with respect to
intercept means that a person spends 68.5 minutes in jogging and no time in running.
intercept means that a person spends 44.2 minutes in running and no time in jogging.