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kiruha [24]
3 years ago
7

Kevin is 333 times as old as Daniel. 444 years ago, Kevin was 555 times as old as Daniel. How old is Kevin now?

Mathematics
2 answers:
My name is Ann [436]3 years ago
8 0

Let D be Daniel's present age, then we can represent Kevin's present age as 3D because Kevin is 3 times as old as Daniel.

We can write an expression for Daniel's age 4 years ago as D-4 and Kevin's age 4 years ago as 3D-4.

We are told that 4 years ago Kevin was 5 times as old as Daniel. We can write this information as:

3D-4=5\cdot(D-4)

Now let us solve our equation to find Daniel's present age.

3D-4=5D-20

-4+20=5D-3D

16=2D

D=\frac{16}{2}=8

Daniel's present age is 8 years. Now we will multiply 8 by 3 to get Kevin's present age as Kevin is 3 times old as Daniel.

\text{Kevin's present age}=8\cdot3=24

Therefore, Kevin is 24 years old now.  

Sophie [7]3 years ago
3 0

Answer:

Daniel is 8 years old

Step-by-step explanation:

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Maggie’s brother is three years younger than twice her age. The sum of their ages is 24. How old is maggie?
JulsSmile [24]

To solve this problem, we must set up a system of equations. In this case, let's let Maggie's age be represented by the variable m and her brother's age be represented by the variable b. We are told that the sum of their ages is 24, which gives us our first equation: m + b = 24. We can construct our next equation from the first sentence of given information: b = 2m - 3. This makes our system of equations:

m + b = 24

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Finally, we should divide both sides by 3 in order to get the variable m alone.

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Therefore, Maggie is 9 years old (using the first equation and substituting in this value you can find that her brother is 15 years old).

Hope this helps!

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