Please answer these two questions..

In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p

hichkok12 [17]

Answer:

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

4 0

3 years ago

How can you tell from a table of values if a relationship is proportional?

dusya [7]

C- in the table every ratio y/x is equal so the relationship is proportional

4 0

3 years ago

Nicholas buys 3/8 pounds of cheese he puts the same amount of cheese on three sandwiches how much cheese does Nicholas put on ea

Lunna [17]

Divide the 3/8 by three. which would be 1/8

5 0

3 years ago

Are the following even, odd, or neither f(x)=5x^3-2x

kaheart [24]

Answer:

positive

Step-by-step explanation:

if x is positive then for all values 5x^3 which is always>-2x will be positive and therefore answer always positive

if x is negative then 5x^3 will always be positive and -2(X) will cancel the two minuses -- and will add therefore positive

6 0

3 years ago

ziggy sells coffee and donuts , the total number of cofees and donuts ziggy sells today is 100. Ziggy charges 3$ for coffee and

sergejj [24]

You use a system of equations
x= coffee
y= donuts
x+y=100
3x+y=180
there’s 3 ways to solve system of equations substitution graphing and elimination. it would be easiest to use substitution here. So you multiply x+y=100 by -1 so it become -x-y=-100. then you combine it with the other equation and get 2x=80 so x=40 which means 40 cups of coffee were sold then you plug it back in to find y. 40+y=100. y=60.
y= 60 (donuts). x= 40 (coffee)

6 0

3 years ago