Since AM = 2cm and AC = 6cm we can write the following:
AM + AC = 8cm
So, now we only create a fraction demonstration the length from AM to AC:
which can be simplified to 
Conclusion/answer:
The length from AM to AC is:
Hope it helped,
BioTeacher101
Answer: They should cross at 6,-1
Step-by-step explanation:
Given:
height = 6m
chord = 20 m
We need to find the radius of the circle.
20 m = 2 √ [ 6m( 2 x radius - 6 m ) ]
20 m / 2 = 2 √<span>[ 6m( 2 x radius - 6 m ) ] / 2 </span>
10 m = √<span> [ 6m( 2 x radius - 6 m ) ] </span>
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ²
100 m²<span> = 6 m( 2 x radius - 6 m ) </span>
100 m²<span> = 12 m x radius - 36 sq m </span>
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m²
136 m²<span> = 12 m x radius </span>
136 m²<span> / 12 m = 12 m x radius / 12 m </span>
<span>11.333 m = radius
</span>
the area beneath an arc:
<span>Area = r</span>²<span> x arc cosine [ ( r - h ) / r ] - ( r - h ) x </span>√<span>( 2 x r x h - h</span>²<span> ).
</span>
<span>r</span>²<span> = (11.333 m)</span>²<span> = 128.444 m</span>²<span> </span>
<span>r - h= 11.333 m - 6 m = 5.333 m </span>
<span>r * h = 11.333 m x 6 m = 68 m</span>²
<span>Area = 128.444 m</span>²<span> x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x </span>√<span>[ 2 x 68 m</span>²<span> - 36 m</span>²<span> ] </span>
<span>Area = 128.444 m</span>²<span> x arc cosine [ 0.4706 ] - 5.333 m x </span>√<span> [ 100m</span>²<span> ] </span>
<span>Area = 128.444 m</span>²<span> x 1.0808 radians - 5.333 m x 10 m </span>
<span>Area = 138.828 m</span>²<span> - 53.333 m</span>²<span> </span>
<span>Area = 85.4 m</span>²
Answer:
The number is 8.
Step-by-step explanation:
Rewrite the word problem as an equation.
The sum of (we will be adding.), half of a number (we can use x, this will be written as x/2.) and double the number (this will be written as 2x) is 20.
To find the number, solve the equation.
x/2 + 2x = 20
Multiply both sides by 2.
x + 4x = 40
Combine terms.
5x = 40
Divide both sides.
x = 8.
