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4 years ago

Need help pls and thank you

Mathematics

2 answers:

Ganezh [65]4 years ago

7 0

The answer is b. The others don’t make sense

mars1129 [50]4 years ago

5 0

Answer: c

Step-by-step explanation: x1+x2/2 , y1+y2/2

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Which ordered pair is the solution to the system of equations? 2x-5y=-5 x+2y=11

oee [108]

2x-5y= -5
-2/*x+2y=11

2x-5y= -5
-2x-4y= -22
+------------------
-9y=-27
y=3

x+2y=11
x+2*3=11
x=5

7 0

4 years ago

Read 2 more answers

The graph of F(x) shown below resembles the graph of G(x)= x4, but it has

Gemiola [76]

Answer:

x = 0.

Equation:

$g*(x)-(x^4)=0$

Step-by-step explanation:

Step 1:

Pull out like factors:
$gx - x^4 = x * (g - x^3)$

Trying to factor as a Difference of Cubes:

Factoring: $g - x^3$
Theory : A difference of two perfect cubes, a^3 - b^3 can be factored into
(a-b) • (a^2 +ab +b^2)
Proof : (a-b)•(a^2+ab+b^2) =
a^3+a^2b+ab^2-ba^2-b^2a-b^3 =
a^3+(a^2b-ba^2)+(ab^2-b^2a)-b^3 =
a^3+0+0-b^3 =
a^3-b^3
Check : g^1 is not a cube !!
Ruling : Binomial cannot be factored as the difference of two perfect cubes

Equation at end of step 1:

$x * (g - x^3) = 0$

Step 2:

A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

Solve $g - x^3 = 0$
In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
We shall not handle this type of equations at this time.

Solution:

x=0.

3 0

3 years ago

At a Noodles & Company restaurant, the probability that a customer will order a nonalcoholic beverage is .51.

satela [25.4K]

Answer:

$P(x\geq 7)=0.1886$

Step-by-step explanation:

The variable x, that said the number of customer that will order a nonalcoholic beverage in a sample of n customers follows a binomial distribution. Because we have n identical and independent events with a probability p of success and (1-p) of fail.

So, the probability that x customers will order a nonalcoholic beverage is:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}$

Where n is the size of the sample and p is the probability that a customer order a nonalcoholic beverage, so replacing the values, we get:

$P(x)=\frac{10!}{x!(10-x)!}*0.51^{x}*(1-0.51)^{10-x}$

Now, the probability that at least 7 will order a nonalcoholic beverage is equal to:

$P(x\geq 7)=P(7)+P(8)+P(9)+P(10)$

Where:

$P(7)=\frac{10!}{7!(10-7)!}*0.51^{7}*(1-0.51)^{10-7}=0.1267\\P(8)=\frac{10!}{8!(10-8)!}*0.51^{8}*(1-0.51)^{10-8}=0.0494\\P(9)=\frac{10!}{9!(10-9)!}*0.51^{9}*(1-0.51)^{10-9}=0.0114\\P(10)=\frac{10!}{10!(10-10)!}*0.51^{10}*(1-0.51)^{10-10}=0.0011$