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Harman [31]
4 years ago
11

Need help pls and thank you

Mathematics
2 answers:
Ganezh [65]4 years ago
7 0
The answer is b. The others don’t make sense
mars1129 [50]4 years ago
5 0

Answer: c

Step-by-step explanation: x1+x2/2 , y1+y2/2

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Five computer program modules are ranked as M1, M2, M3, M4, and M5 according to the ascending order of effort required to debug
gulaghasi [49]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Technician selects three out of 5 systems  

In C(5,3)=10ways, this can be achieved  

In part a:

Space sample chooses 3 of a 5 systems  

(M_1, \ M_2,\ M_3),(M_1,M_2,M_4) \ (M_1,M_2,M_5) \ (M_1,M_3,M_4) \ (M_1,M_3,M_5),(M_1,M_4,M_5) \ (M_2,M_3,M_4)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5)}

In point b:

A =MODULE WHICH INCLUDE M1 minimal amount of effort  

Outcomes probable =

(M_1,M_2,M_3),\ (M_1,M_2,M_4) \ (M_1,M_2,M_5)\ (M_1,M_3,M_4)\\\\(M_1,M_3,M_5),\ (M_1,M_4,M)5)\ =\ 6

\to p(A)=\frac{6}{10}\\\\

            =0.6

In point c:

B = highest effort that is M_5

Potential result=

(M_1,M_2,M_5) \ (M_1,M_3,M_5) \ (M_2,M_3,M_5)\(M_2,M_4,M_5) \\ (M_2,M_4,M_5), \ (M_3,M_4,M_5) \ =\ 6  \\\\

\to B= \frac{6}{10} \\\\

        =0.6

\to P(B)=10

In point d:

\to \ A  \ intersection \ B=(M_1,M_2,M_5), \ (M_1,M_3,M_5) \ ,(M_1,M_4,M_5)

\to A (A \ intersection \ B) = \frac{3}{10} \\\\\ \ \ \ \ \

                                      =0.3

In point e:

\to (A \cup B) =  (M_1,M_2,M_3),\ (M_1,M_2,M_4)\ (M_1,M_2,M_5)(M_1,M_3,M_4)\ (M_1,M_3,M_5), \\ (M_1,M_4,M_5)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5) \ = \ 9\to P(A \cap B)=\frac{9}{10}

                    = 0.9

In point f:

\to (A\cap B) = \frac{3}{10}

                 = 0.3

In point g:

\to (A \cup B) = \frac{7}{10}

                 =0.7

In point h:

\to p(A \cap B) = 0.3 \neq 0

8 0
3 years ago
Write the number in standard form.<br> 7 x 107
laila [671]

Answer:

<u>749</u>

Step-by-step explanation:

Break apart the equation:

(7 x 100) + (7 x 7)

7 x 100 = 700

7 x 7 =49

700 + 49 = 749

Hope this helps

3 0
3 years ago
4.) The graph below shows that the cost of bananas depends on the number of pounds
Alina [70]

Answer: B.$1.25

Step-by-step explanation: 10 divided by 1.25= 8 pounds

8 0
3 years ago
Read 2 more answers
How dose north america achieve 480VAC with 3 pole 120VAC
makvit [3.9K]

Answer:

There are a variety of factors driving the

adoption of 415/240VAC distribution. First,

distributing at these increased voltages

enables overall efficiency to be enhanced

by eliminating the need for a voltage

transformation along the power path. For

example, in a 415V system, the L-N voltage

is 240V, which is compatible with most all IT

loads. By shifting the UPS output distribution

voltage to 415/240 V three-phase (L-L/

L-N), most of the existing servers today can

be powered with 240V single-phase (L-N)

without any intermediate transformation.

Removing the need for a transformer

streamlines the power path and can increase

efficiency approximately 1.5 percent.

The adoption of a 415/240VAC distribution

model also can yield additional savings at

the device-level in the form of increased

efficiency for server power supplies. As

previously mentioned, today’s power

supplies can handle a wide range of incoming

voltages. Based on the actual voltage being

fed into the power supply, efficiencies can

range from as low as 80 percent (at 100V

nominal) to as much as 94 percent (at 240V

nominal) across all manufacturers.

Furthermore, while the typical efficiency

differential between 240V and 208V gained

at the server power supply today is a relatively

minimal, only 0.3 percent across most of

the load range, the efficiency differential

between 240V and 120V servers can be as

much as 2 percent for a given power supply.

It is this value that often gets overstated by

some manufacturers when comparing 415V

distribution to “traditional methods,” as

there are relatively few servers or peripherals

installed today that are operating at 120V.

Step-by-step explanation:

7 0
3 years ago
A banner is in the shape of a right triangle. the area is 63 inches. The height of the banner is 4 in less than twice the width
Blizzard [7]
Area=1/2 times base times height
note:bh=base times height

a=1/2bh
b=width

h=-4+2w
h=2w-4
subsitute
a=1/2w(2w-4)
a=1/2(2s^2-4w)
a=w^2-2w
a=63
63=w^2-2w
subtract 63 from both sdies
0=w^2-2w-63
factor
find what 2 numbers multiply to get -63 and add to get -2
the numbers are -9 and 7
so
0=(w-9)(w+7)
if xy=0 then x and/or y=0

so
w-9=0
w+7=0

solve each
w-9=0
add 9 to both sdies
w=9

w+7=0
subtract 7 from both sides
w=-7
width cannot be negative so this can be discarded

width=9

subsitute
l=2w-4
l=2(9)-4
l=18-4
l=14


legnth=14 in
width/base=9 in
5 0
3 years ago
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