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dusya [7]
3 years ago
12

Marco solves the equation 4sin(3x) + 0.25 ≤ 2sin(3x) − 0.3 by graphing y = 2sin(3x) and y = −0.55. he then locates the intervals

on which 2sin(3x) is less than or equal to −0.55. is marco's solution method valid? explain.
Mathematics
2 answers:
raketka [301]3 years ago
8 0
Help me with this please 
ch4aika [34]3 years ago
6 0

Answer:

yes, Marco's method is correct.

The given inequality can be rewritten using the properties of inequality.

You can subtract 2sin(3x) and 0.25 from both sides of the inequality.

Subtracting preserves the direction of the inequality, so 2sin(3x) would be less than or equal to –0.55.

Step-by-step explanation:


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Answer:

Choice 3 is your answer

Step-by-step explanation:

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f(x) = (x - h) + k,

where h is the side to side movement and k is up or down.  The k is easy, since it will be positive if we move the function up and negative if we move the function down from its original position.

The h is a little more difficult, but just remember the standard form of the side to side movement is always (x - h).  If our function has moved 3 units to the left, we fit that movement into our standard form as (x - (-3)), which of course is the same as (x + 3).  Our function has moved up 5 units, so the final translation is

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3 years ago
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coldgirl [10]

Assignment: \bold{Simplify \ Equation: \ 7\left(3\sqrt{2}x\right)-3\left(3\sqrt{16}x\right)-3\left(3\sqrt{8}x\right)}

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Answer: \boxed{\bold{3\sqrt{2}x-36x}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Remove Parenthesis (a) = a

\bold{7\cdot \:3\sqrt{2}x-3\cdot \:3\sqrt{16}x-3\cdot \:3\sqrt{8}x}

[ Step Two ] Simplify Equations

\bold{7\cdot \:3\sqrt{2}x: \ 21\sqrt{2}x}

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[ Step Three ] Rewrite Equation

\bold{21\sqrt{2}x-36x-18\sqrt{2}x}

[ Step Four ] Add Similar Elements

\bold{21\sqrt{2}x-18\sqrt{2}x=3\sqrt{2}x}

[ Step Five ] Rewrite Equation

\bold{3\sqrt{2}x-36x}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

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Question 12
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Nadusha1986 [10]
Check the picture below.

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because the point 0,0 yielded a false inequality, that region is the "false region" and thus not shaded, therefore, the other side must be the "true region", and thus we shade that then.

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