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otez555 [7]
3 years ago
9

The width of a rectangle is 2 meters less than the length. The area of the rectangle is 15m. Find

Mathematics
2 answers:
NARA [144]3 years ago
6 0

Answer:

The length is 5 meters and the width is 3 meters.

Step-by-step explanation:

bazaltina [42]3 years ago
3 0

Answer:

Length is 5 meters. Width is 3 meters.

Step-by-step explanation:

I dont really have one

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Assume that there is a 4​% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit
kap26 [50]

Answer:

a) 99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b) 99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

4​% rate of disk drive failure in a year.

This means that 96% work correctly, p = 0.96

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk​ drive, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 2

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984

99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b. If copies of all your computer data are stored on four independent hard disk​ drives, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 4

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.96)^{0}.(0.04)^{4} = 0.00000256

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.00000256 = 0.99999744

99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

7 0
3 years ago
What is 14 1/6 minus 7 1/3
Levart [38]
Yes I agree 6 5/6 yeet big boi
6 0
3 years ago
Represent each sum as a single rational number.<br> 7 + (1/9)
Nady [450]

Answer:

Do u have a picture of it

Step-by-step explanation:

5 0
3 years ago
Is 2.12359..... rational???​
den301095 [7]

Answer:

No

Step-by-step explanation:

Rational numbers are those that can be represented in a fraction form.

2.12359.... cannot be represented in a fraction form.

So, it is NOT a rational number

6 0
3 years ago
Read 2 more answers
Solve the equation C=2πr for π
postnew [5]
C = 2πr   Divide both sides by 2r
\frac{C}{2r} = π   Switch the sides to make it easier to read
π = <span>\frac{C}{2r}</span>
7 0
3 years ago
Read 2 more answers
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