Givens
Petri Dish A sees a double ever 10 minutes
Petri Dish B sees a double ever 6 minutes
Consequences
A doubles 60 / 10 = 6 times.
B doubles 60 / 6 = 10 times.
Solution
If you work best with numbers then suppose there are 100 bacteria in both dishes at the beginning
A = 100 * 2^6
B = 100 * 2^10
A will have 100 * 64 = 6400 bacteria growing inside A
B will have 100 * 1024 = 102400 bacteria growing inside B
B/A = 102400 / 6400 = 16
There are 16 times as many in B than in A. <<<< Answer
Answer:
1 2/3 = 1 8/12
Step-by-step explanation:
2/3 * 4/4 because 3*4= 12 is 8/12 hope this helps :)
Y=20+35x because the 20 is a 1 time thing and 35x because 35 is charged each month
The constant variation k is 12
Answer: I believe it's 6 5/8
Step-by-step explanation:
