Answer:
see below
Step-by-step explanation:
Any line between two points on the circle is a chord.
Any angle with sides that are chords and with a vertex on the circle is an inscribed angle.
Any angle with sides that are radii and a vertex at the center of the circle is a central angle. Each central angle listed here should be considered a listing of two angles: the angle measured counterclockwise from the first radius and the angle measured clockwise from the first radius.
<h3>1.</h3>
chords: DE, EF
inscribed angles: DEF
central angles: DCF . . . . . note that C is always the vertex of a central angle
<h3>2.</h3>
chords: RS, RT, ST, SU
inscribed angles: SRT, RSU, RST, RTS, TSU
central angles: RCS, RCT, RCU, SCT, SCU, TCU
<h3>3.</h3>
chords: DF, DG, EF, EG
inscribed angles: FDG, FEG, DFE, DGE
central angles: none
<h3>4.</h3>
chords: AE
inscribed angles: none
central angles: ACB, ACD, ACE, BCD, BCE, DCE
I believe the product is 5x. Hope that helps :)
It means that those 2 angles are the exact same length
Answer:
39 km/h
Step-by-step explanation:
Velocity is the rate of change of distance in a given direction with time. Mathematically,
Velocity = Displacement/time
Like speed, velocity is measured in Km/h or m/s.
Given that the car travels at 54 km/h for first 20seconds,
since 60 seconds = 1 minute and
60 minutes = 1 h,
20 seconds
= 20/(60 ×60) h
= 1/180 h
In the same vein,
30 seconds
= 30 / (60 ×60) h
= 1/120 h
10 seconds
= 10/(60 ×60) h
= 1/360 h
Hence if the car travels 54 km/h for 10 seconds, the distance covered
= 54 × 1/180
= 3/10 Km
If the car travels 36km/h for next 30seconds, the distance covered
= 36 × 1/120
= 3/10 Km
If the car travels 18km/h for next 10 seconds, the distance covered
= 18 × 1/360
= 1/20 km
Total distance = 3/10 Km + 3/10 Km + 1/20 Km
= 13/20 Km
Total time spent = 20 + 30 + 10
= 60 seconds
= 1/60 h
Average velocity = 13/20 km/ 1/60 h
= 39 Km/h
Answer: does not make sense.
The statement " t<span>he beach ball we played with has a density of 10 grams per cubic centimeter" does not make sense.
Reasoning.
Inflated beach balls have a very low density, they are pretty much only air, plus the weight of the ball per se. Certainly that density is much lower than the density of water.
Inflated beach balls fall slowly in the air because their density is very close to the density of air and float on water because their density is less than the density of water.
Being the density of pure water 1 g/cm^3 you can predict, without any calculation, that the density of the beach ball is less than that and never 10 g/cm^3 which is 10 times the density of pure water.
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