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kirill [66]
3 years ago
6

a car travels at 54 km/h for first 20seconds , 36km/h for next 30seconds and finally 18km/h for next 10 seconds find the averade

velocity
Mathematics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

39 km/h

Step-by-step explanation:

Velocity is the rate of change of distance in a given direction with time. Mathematically,

Velocity = Displacement/time

Like speed, velocity is measured in Km/h or m/s.

Given that the car travels at 54 km/h for first 20seconds,

since 60 seconds = 1 minute and

60 minutes  = 1 h,

20 seconds

= 20/(60 ×60) h

= 1/180 h

In the same vein,

30 seconds

= 30 / (60 ×60) h

= 1/120 h

10 seconds

= 10/(60 ×60) h

= 1/360 h

Hence  if the car travels 54 km/h for 10 seconds, the distance covered

= 54 × 1/180

= 3/10 Km

If the car travels 36km/h for next 30seconds, the distance covered

= 36 × 1/120

= 3/10 Km

If the car travels 18km/h for next 10 seconds, the distance covered

= 18 × 1/360

= 1/20 km

Total distance = 3/10 Km + 3/10 Km + 1/20 Km

= 13/20 Km

Total time spent = 20 + 30 + 10

= 60 seconds

= 1/60 h

Average velocity = 13/20 km/ 1/60 h

= 39 Km/h

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Step-by-step explanation:

It is given that Point A is at (-5, -4) and point B at (-3, 3).

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First of all you have to consider the shaded region. It is bound by two lines.

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the second line is the broken line. it passes through the origin (0,0) and (1,1) any two points can be taken. the gradient is 1. m= (y1-y2)/(x1-x2) = (0-1)/(0-1)=(-1/-1)= 1. the equation of a straight line is

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