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3 years ago

Allison runs for 1 3/4 minutes and travels 1/5 mile. What is her speed in miles per minute?

Mathematics

1 answer:

Mars2501 [29]3 years ago

6 0

41.5 jus look it up on the internet

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Find the product of ( 2a2– 3b2) and ( a +b2- 3z)

Bond [772]

Answer:

$2a^3+2a^2b^2-6a^2z-3ab^2-3b^4+9b^2z$

Step-by-step explanation:

$(2a^2-3b^2)(a+b^2-3z)$

Start by distributing the $2a^2$ into all of the terms in between the second parentheses.

$2a^3+2a^2b^2-6a^2z$

Next, distribute the $-3b^2$ into all of the terms in between the second parentheses.

$-3ab^2-3b^4+9b^2z$

For the sake of simpler interpretation, I separated the two above, but they are together:

$2a^3+2a^2b^2-6a^2z-3ab^2-3b^4+9b^2z$

Since the terms are already in descending order, we do not need to rearrange them.

4 0

3 years ago

What is 50% of 150 =

Nady [450]

Yeah what they said

6 0

3 years ago

Kyra went to the grocery store on Monday and bought 5 apples and 2 oranges for a total of $3.45. On Thursday she bought 3 orange

MArishka [77]

Answer: $6.60

Hope this helps

4 0

2 years ago

The Chang family is on their way home from a cross-country road trip. During the trip, the function D(t)=3260−55t can be used to

nadya68 [22]

Answer:

D(12) = 2,600 miles

It means a distance of 2,600 miles is already traveled from home after 12 hours

Step-by-step explanation:

To find D(12); all we have to do is to substitute the value of 12 for D

We have this as;

D(12) = 3260-55(12)

D(12) = 2,600

In the context of this problem, what this mean is that the distance away from home is 2,600 miles after traveling 12 hours

6 0

3 years ago

ΔABC is dilated using a scale factor of 12 to produce ΔA'B'C'. Select all of the statements that apply to the transformation.

GalinKa [24]

Answer:

Options (3) and (6)

Step-by-step explanation:

ΔABC is a dilated using a scale factor of $\frac{1}{2}$ to produce image triangle ΔA'B'C'.

Since, dilation is a rigid transformation,

Angles of both the triangles will be unchanged or congruent.

m∠A = m∠A' and m∠B = m∠B'

Since, sides of ΔA'B'C' = $\frac{1}{2}$ of the sides of ΔABC

Area of ΔA'B'C' = $\frac{1}{2}(\text{Area of triangle ABC})$

Area of ΔABC > Area of ΔA'B'C'

Since, angles of ΔABC and ΔA'B'C' are congruent, both the triangles will be similar.

ΔABC ~ ΔA'B'C'

Therefore, Option (3) and Option (6) are the correct options.

3 0

3 years ago