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Dimas [21]
3 years ago
5

ONLY NEED TO DO 6, 8, 10, 12, 14.

Mathematics
1 answer:
zimovet [89]3 years ago
7 0

Answer:

  • 6 = (2,2)
  • 8 = (0, -6)
  • 10 =(13,-6)

Step-by-step explanation:

Midpoint = (\frac{x_2+x_1}{2} , \frac{y_2+y_1}{2}  )\\

6.

(5.8) =(x_1,y_1)\\(-1,-4) =(x_2,y_2)\\\\Midpoint =\left(\frac{-1+5}{2},\:\frac{-4+8}{2}\right)\\\\Midpoint =( \frac{4}{2} , \frac{4}{2} )\\\\Midpoint = ( 2 , 2)

8.

(-3 ,-7) =(x_1 ,y_1)\\(3,-5)=(x_2,y_2)\\\\\left(\frac{3-3}{2},\:\frac{-5-7}{2}\right)\\  \\Midpoint = (\frac{0}{2} , \frac{-12}{2} )\\\\Midpoint = ( 0, -6)

10.

L(-9 ,4) =(x_1 ,y_1)\\K(2 , -1 ) = (x ,y )\\M(x_2 ,y_2 )=?\\ \\x = \frac{x_2+x_1}{2}\\ 2 = \frac{x_2 +(-9)}{2}\\ 2 = \frac{x_2-9}{2}\\ Cross\:Multiply\\\\4 =x_2-9\\4+9=x_2\\13 =x_2\\\\y = \frac{y_2+y_1}{2}\\ -1 = \frac{y_2 +4}{2} \\-1 \times 2= y_2+4\\-2 =y_2+4\\-2-4 =y_2\\-6 =y_2\\\\(x_2 ,y_2) = (13 , -6)\\

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Help me please i need some help.
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Answer:

2,5, 6

Step-by-step explanation:

a coefficient is the number placed before the variable in equations and the other numbers, in this case 7 and 4, are called constants

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3 years ago
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you can subtract from point 1 to point 2

(9,-2) - (8,3)

9-8= 1

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3 years ago
Which expression is equivalent to 5(4f+3)-2f
Ierofanga [76]

Answer:

f = 5/6

Step-by-step explanation:

5(4f + 3) - 2f

= 20f + 15 - 2f

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At which points are the tangents drawn to the ellipse x 2 + y 2 = [ a ] x + [ a ] y parallel to
In-s [12.5K]

The given equation of the ellipse is x^2 + y^2 = 2 x + 2 y

At tangent line, the point is horizontal with the x-axis therefore slope = dy / dx = 0

<span>So we have to take the 1st derivative of the equation then equate dy / dx to zero.</span>

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x^2 – 2 x = 2 y – y^2

(2x – 2) dx = (2 – 2y) dy

(2x – 2) / (2 – 2y) = 0

2x – 2 = 0

x = 1

 

To find for y, we go back to the original equation then substitute the value of x.

x^2 + y^2 = 2 x + 2 y

1^2 + y^2 = 2 * 1 + 2 y

y^2 – 2y + 1 – 2 = 0

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Finding the roots using the quadratic formula:

y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1

y = 1 ± 2.828

y = -1.828 , 3.828

 

<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828) and (1, 3.828).</span>

3 0
4 years ago
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