This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
.
Step-by-step explanation:
Answer:
25%
Step-by-step explanation:
This question is about conditional probability. Let's say that the probability of raining on Saturday is X=true and the probability of raining on Sunday is Y=true. There is a 15% it will rain on both Saturday and Sunday, to put into the equation it will be:
P(X= true ∩ Y = true) = P(X = true) * P(Y = true)= 0.15
There is a 60% chance of rain on Saturday, mean the equation is
P(X = true) = 0.6
The question is asking for the chance of rain on Sunday or P(Y = true). If we substitute the second equation to first, it will be:
P(X = true) * P(Y = true)= 0.15
0.6* P(Y = true)= 0.15
P(Y = true)= 0.15/0.6
P(Y = true)= 0.25 = 25%
Answer:
the answer is ac line segment
