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3 years ago

Solve: g^2x+1=g^3x-2 x=?

Mathematics

1 answer:

Schach [20]3 years ago

6 0

Answer:

the answer you will be looking for is g^2x - g^3x = -3

Step-by-step explanation:

as much as I would like to, I'm really not that great at explaining things

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Algebra need to solve question

Zigmanuir [339]

Answer:

Step-by-step explanation:

$(3+\sqrt{7})(3-\sqrt{7}) \\$

First do 3 x 3 = 9 - keep this 9 to the side for now

Then do 3 x $-\sqrt{7}$ = $-\sqrt{21}$ - also keep this to the side for now

Then do $\sqrt{7}$ x 3 = $\sqrt{21}$

Then do $-\sqrt{7}$ x $\sqrt{7}$ = -7

So,

9 $-\sqrt{21}$ + $\sqrt{21}$ - 7

Therefore, 9-7 = 2

4 0

3 years ago

I need help no ilnks please and thank you

Elza [17]

Answer:

yep

Step-by-step explanation:

nice

8 0

3 years ago

Help ill give you 25 points

lisov135 [29]

Answer:

Step-by-step explanation:

3n+2 is divisible by p:

3n + 2 = px

8n+3 is divisible by p:

8n + 3 = py

Solve each equation for n:

n = (px - 2)/3
n = (py - 3)/8

Eliminate n and solve for p:

(px - 2)/3 = (py - 3)/8
8(px - 2) = 3(py - 3)
8px - 16 = 3py - 9
8px - 3py = 7
p = 7/(8x - 3y)

As we see p could get 1 or 7 as natural number. Since 1 is excluded, the only solution is 7, and 8x - 3y must equal to 1.

7 0

3 years ago

How is using partial products to find the product of two 2-digit factors similar to how you have used partial products in the pa

klasskru [66]

Well the multiplication part is the same .Its in the ordering it has to be(ex: 42 times 35) but it has to be placed vertically .For the second number multiply to the right then the left .Repeat .Then you got your answer using 2 digits similar to regular multiplication partial products .Hope this helped !!

4 0

3 years ago

Read 2 more answers

Show that tanø+Cotø = Secø Cosecø

LiRa [457]

Answer:

True.

Keys:

Manipulate left/right sides

Step-by-step explanation:

$\tan \left(\theta\right)+\cot \left(\theta\right)=\sec \left(\theta\right)\csc \left(\theta\right)\\\tan \left(\theta\right)+\cot \left(\theta\right)\\=\frac{\cos ^2\left(\theta\right)+\sin ^2\left(\theta\right)}{\cos \left(\theta\right)\sin \left(\theta\right)}\\=\frac{1}{\cos \left(\theta\right)\sin \left(\theta\right)}\\\\\sec \left(\theta\right)\csc \left(\theta\right)\\=\frac{1}{\cos \left(\theta\right)\sin \left(\theta\right)}$

What was shown throughout this problem?

We showed that two different sides are capable of taking the same form.

8 0

2 years ago