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2 years ago

Solve: g^2x+1=g^3x-2 x=?

Mathematics

1 answer:

Schach [20]2 years ago

6 0

Answer:

the answer you will be looking for is g^2x - g^3x = -3

Step-by-step explanation:

as much as I would like to, I'm really not that great at explaining things

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Which two ratios represent qauntities that are proportional

Leokris [45]

Are there answer choices ?

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3 years ago

The total scores on the Medical College Admission Test (MCAT) follow a Normal distribution with mean 25.2 and standard deviation

erica [24]

Honey God is good god bless u with that hw

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3 years ago

Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed between 1pm and 7p

Ymorist [56]

Answer:

$E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours$

$Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2$

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

$A\sim Uniform(1 ,7)$

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

$B\sim Exp(\lambda=\frac{1}{30 min})$

Supposing that the two times are independent, find the expected value and the variance of the time at which the plumber completes the project.

So we are interested on the expected value of A+B, like this

$E(A +B)$

Since the two random variables are assumed independent, then we have this

$E(A+B) = E(A)+E(B)$

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

$E(A)=\frac{1+7}{2}=4 hours$

The expected value for the exponential distirbution is given by :

$E(X)= \int_{0}^\infty x \lambda e^{-\lambda x} dx$

If we use the substitution $y=\lambda x$ we have this:

$E(X)=\frac{1}{\lambda} \int_{0}^\infty y e^{-\lambda y} dy =\frac{1}{\lambda}$

Where X represent the random variable and $\lambda$ the parameter. If we apply this formula to our case we got:

$E(B) =\frac{1}{\lambda}=\frac{1}{\frac{1}{30}}=30min$

We can convert this into hours and we got E(B) =0.5 hours, and then we can find:

$E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours$

And in order to find the variance for the random variable A+B we can find the individual variances:

$Var(A)= \frac{(b-a)^2}{12}=\frac{(7-1)^2}{12}=3 hours^2$

$Var(B) =\frac{1}{\lambda^2}=\frac{1}{(\frac{1}{30})^2}=900 min^2 x\frac{1hr^2}{3600 min^2}=0.25 hours^2$

We have the following property:

$Var(X+Y)= Var(X)+Var(Y) +2 Cov(X,Y)$

Since we have independnet variable the Cov(A,B)=0, so then:

$Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2$

3 0

3 years ago

How to round 0.195121951 to the nearest hundredth of a percent

tigry1 [53]

Answer:

You have to look at the second number in the decimal place and round the number to the right of it. 0.20

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3 years ago

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T. The entropy change As, for an ideal gas is given by the following formula: dT dV As=1C [c. R T V 7 where T is the thermodynam

MissTica

Answer:

The entropy change AS, for an ideal gas is given by: dt V Where T is the thermodynamic temperature, V is the volume and R=8.314. Determine the entropy change when a gas expands from 1 litre to 3 litres for a temperature rise from 100K to 400K given that: Cv = 45 + 6 x 10-T + 8 x 10-6T2 b) The average value of a complex voltage waveform is given by: V = ( 10 (10sin ox +3sin 30x +2 sin 508) dt Evaluate Vav correct to 2 decimal places.

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2 years ago