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Maurinko [17]
2 years ago
15

Identify each property a. a(b+c) = ab + c . b: (a+b) + c = a + (b+c)

Mathematics
1 answer:
slava [35]2 years ago
7 0
A is distributive property.
B is associative property.
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
kodGreya [7K]

y^2 (y + 2) + 16(y + 2)

(y+2) (y^2+16)

3 0
3 years ago
Can u help me with these math problems
Vlada [557]

Answer:

Q3: A

Q4: 9x² + (-x) + (-3)

Step-by-step explanation:

Q3: C (63) => x = 63. => C(x) = 36 x 63

Q4: f(x) + g(x) = 7x² - 5x + 3 + 2x² + 4x - 6 = (7x² + 2x²) + (-5x + 4x) + (3 - 6) = 9x² + (-x) + (-3)

8 0
3 years ago
Write the standard form of the equation of the circle that passes through the point
AnnZ [28]

Answer:

The standard form of the equation of the circle is x^2+y^2=1.

Step-by-step explanation:

A circle is the set of points in a plane that lie a fixed distance, called the radius, from any point, called the center.

The equation of a circle in standard form is

                                             (x-h)^2+(y-k)^2=r^2

where <em>r</em> is the radius of the circle,  and <em>h</em>, <em>k</em> are the coordinates of its center.

When the center of the circle coincides with the origin h=k=0, so

                                            (x-0)^2+(y-0)^2=r^2\\x^2+y^2=r^2

We are also told that the circle contains the point  (0, 1), so we will use that information to find the radius <em>r</em>.

                                                   0^2+1^2=r^2\\r^2=0^2+1^2\\r^2=1\\r=\sqrt{1}

Therefore, the standard form of the equation of the circle is x^2+y^2=1.

5 0
3 years ago
Answer from least to greatest 9 -11 -8 12 3
Thepotemich [5.8K]
\begin{gathered} -11 \\ -8 \\ 3 \\ 9 \\ 12 \end{gathered}

remember a number is least when

3 0
1 year ago
How to find the multiplicity of a zero of a polynomial function?
Monica [59]
<span>The multiplicity of a zero of a polynomial function is how many times a particular number is a zero for a given polynomial.

For example, in the polynomial function f(x)=x(x+4)^2(x-2)^3, the zeros are 0 with a multiplicity of 1, -4 with a multiplicity of 2, and 2 with a multiplicity of 3.

Although this polynomial has only three zeros, we say that it has six zeros (or degree of 6) counting the <span>multiplicities.</span></span>
3 0
3 years ago
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