PLZZ HELP ME THIS IS DUE TODAY!!!!
2 answers:
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1) all the possible genotypes are also identified by color in the image below :AABBAAbB or AABbaABB or AaBBaAbB or aABb or AabB or AaBbAAbb
aAbb or AabbaaBB
aabB or aaBbaabbThere are 9 different genotypes in total. These can be achived by mixing the alleles of both genes of each parent (just like it's represented in the square).
2) there are 4 phenotypes
-one with an allele A and allele B that would dominate the other. (AABB, aAbB, for example)
- one with all alleles recessive- aabb
-one with the recessive alleles in the gene A but heterozygotic/homozigotic dominant for gene B ( for example: aaBB)
-one with the recessive alleles in the gene B but heterozygotic/homozigotic dominant for gene A ( for example: Aabb)
3) <span>probability of having offspring with the aabb genotype: 1/16
Just by looking at the punnet square, you can see that only one has the aabb genotype, in all the 16 possibilities.
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aAbb or AabbaaBB
aabB or aaBbaabbThere are 9 different genotypes in total. These can be achived by mixing the alleles of both genes of each parent (just like it's represented in the square).
2) there are 4 phenotypes
-one with an allele A and allele B that would dominate the other. (AABB, aAbB, for example)
- one with all alleles recessive- aabb
-one with the recessive alleles in the gene A but heterozygotic/homozigotic dominant for gene B ( for example: aaBB)
-one with the recessive alleles in the gene B but heterozygotic/homozigotic dominant for gene A ( for example: Aabb)
3) <span>probability of having offspring with the aabb genotype: 1/16
Just by looking at the punnet square, you can see that only one has the aabb genotype, in all the 16 possibilities.
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