(96+92+80+91+86+x)= 90
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6
(445+x)=90
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6
then you multiply 6 on both sides
445+×=540
-445. -445
x= 95
they need a 95 percent to have an average of a 90%.
Two and one thirds will be located between 2 and 3.
hope this helps :)
We can use a ratio:
First measurements:second measurements
We have 5:10 for example.
Looking at the ratio, you can tell that the second set of measurements are double than the first.
We have to solve 10:Y
Since it's double, just multiply 10 by 2.
10×2
20
So, the last answer is correct.
I would say this 0.14411825688 I might be wrong