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maxonik [38]
3 years ago
6

A medical office is replacing their existing flooring with carpeting in the waiting and office areas and laminate flooring in th

e patient exam rooms. If each of the 10 exam rooms is 10 feet by 10 feet, the waiting area is 20 feet by 15 feet, and the office area is 25 by 20 feet, how many total square feet of flooring will they be replacing?
Mathematics
1 answer:
Leokris [45]3 years ago
7 0
(10 x area of exam room) + area of waiting are + Area of office area

10 x (10 x 10) + (20 x 15) + (25 x 20) 
1000 + 300 + 500
= 1800 square feet
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slava [35]

Step-by-step explanation:

1.

\tan \beta  =  \frac{1}{ \cot \beta }  =  -  \frac{3}{2 \sqrt{10} }  =  -  \frac{3 \sqrt{10} }{20}

\csc \beta  \tan \beta  =  \frac{1}{ \cos \beta  }  =  \sec \beta

Therefore,

\sec \beta  = ( \frac{7}{3} )( -  \frac{3 \sqrt{10} }{20} ) =  -  \frac{7 \sqrt{10} }{20}

2.

\csc y =  \frac{1}{ \sin y}  =  -  \frac{ \sqrt{6} }{2}

=  >  \sin y =  -  \frac{ \sqrt{6} }{3}

Use the identity

\cos y =   \sqrt{1 -  \sin ^{2} y}    \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \\ =  \sqrt{1 -  {( -  \frac{ \sqrt{6} }{3}) }^{2} }  =  -  \frac{ \sqrt{3} }{3}

We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:

\tan \beta  =  \frac{ \sin y}{ \cos y} =( -  \frac{ \sqrt{6} }{3} )( -  \frac{3}{ \sqrt{3} } ) =  \sqrt{2}

3. Recall that sec x = 1/cos x, therefore cos x = 5/6. Solving for sin x,

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Solving for tan x:

\tan x =  \frac{ \sin x}{ \cos x}  =  (\frac{ \sqrt{11} }{ \sqrt{6} } )( \frac{6}{5} ) =  \frac{ \sqrt{66} }{5}

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3 years ago
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Answer:

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0-12= -12

28+12 = 40

28-40 = -12

40 is the increase

40 is half of 80

So, the answer is 80

To check: -12 + 40 (half of a number; 80) = 28

Hope this makes sense. If you require further information, do not hesitate to ask!

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Answer:

I believe it is 6.

Step-by-step explanation:

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