Any of the 4 people can take the first seat
since it gets occupied by one person , the next seat can be occupied by any of the remaining 3
similarly, the next one has 2 possibilities and the last seat can only be occupied by the man who is left
so by the principal of multiplication, no. of ways equals 4! = 4×3×2×1 = 24 ways
Answer:
There are 12 possible outcomes.
Step-by-step explanation:
This question represents combined independent events of probability. Independent events are not affected by previous events. So, your probability is the same with each flip of the coin or roll of the die. So, you just have to look at the total number of outcomes for each and multiply them. Since there are only two sides to a coin, there are only two total outcomes. Since there are six sides to a die, there are only six total outcomes. 2 x 6 = 12 total outcomes.
Answer:
- 2-point shots = 41, 1-point shots = 16
Step-by-step explanation:
Let the number of 1-point shots is x and 2-points shots is y.
The system as per question is
Solve it by elimination, subtract the first equation from the second
- x + 2y - x - y = 98 - 57
- y = 41
Find the value of x
It would be 0.4:) hope this helps
Let's see. We can clarify a few things to make the question easier.
-We bought 10 packs of candy
-M&Ms are $1 per pack
-Twizzlers are $0.5 per pack
We need to find out how many bags of M&Ms we bought by only spending $6.
There are many combinations you can use to get to $6. However, I'm not sure what the format is. For example, you could buy 4 twizzler packs and then use the remaining money to find out how many M&Ms you bought. But this seems to be open to answers. Sorry
