Concept: Solution of the given attachment is based on the addition of two vectors as given below.
Consider two vectors P and Q, then resultant of these two vectors is given as,
R = P + Q
To find the addition of G & H vectors. That is G + H =?
In the given figure;
Vector A = - Vector G because both are in opposite directions -----(i)
From the figure,
A + H = F --------------- using the given concept ---------(ii)
Now, shall replace the value of A from equation (i) in equation(ii)
- G + H = F
or, G + (- H) = - F
Since the vector addition of G & H is not equal to F.
Hence, the given statement G + H = F is False.
Answer:
To dilate line F by a scale factor of 3 in the center of origin multiply points A and B by 3. For example, Point A(x*3,y*3).
Step-by-step explanation:
There are 8 marks on the line and the first line is 3 long while the second is 2 long
c. 3/8+2/8=5/8
Answer:
r = 7
c = 43.98
a = 153.94
Step-by-step explanation:
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
