Step-by-step explanation:
5.
angle STQ is the supplementary angle (together they are 180° below line MQ) to 2x + 8.
above ST we have a group of 3 angles that combine to 180° :
2x + 8
90°
71 - x
so, to get x first :
2x + 8 + 90 + 71 - x = 180
x + 169 = 180
x = 11
so, the angle MTS =
2x + 8 = 2×11 + 8 = 22 + 8 = 30°.
6.
therefore, the angle STQ is
180 - angle MTS = 180 - 30 = 150°.
Part A: slope is 40
And i don’t know the rest I’m sorry
Answer:
- x=8, x=2
- no solution
- no solution
Step-by-step explanation:
For the equation ...
y = a(x -h)² +k
you can find the x-intercepts by setting y=0 and solving for x.
0 = a(x -h)² +k
-k = a(x -h)² . . . . . . subtract k
-k/a = (x -h)² . . . . . divide by a
±√(-k/a) = x -h . . . . take the square root
h ± √(-k/a) = x . . . . add h . . . . this is the general solution
__
So, for each of your problems, fill in the corresponding numbers and do the arithmetic. If (-k/a) is a negative number, the square root gives imaginary values, so there is "no solution".
1. x = 5 ± √9 = {5 -3, 5 +3} = {2, 8} . . . . the x-intercepts are 2 and 8
2. x = -3 ± √(-2) . . . . . . no solution; the roots are complex
3. x = 5 ± √(-8/4) . . . . . no solution; the roots are complex
"<span>y/5+8=7, what is the value of y/5-2?" Simplify the first equation:
y/5 = 7 - 8, or -1, so y/5 = -1, or y = -5.
Then y/5 - 2 equals -5/5 - 2, or -3.</span>
No circle can never be the perfect squares
