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Oksanka [162]
3 years ago
6

Could a triangle have lengths of the sides of 4,8,6,2

Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0

yez they can but it depend on wat type of triangle

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I need help please! ​
lesantik [10]

Answer:

the correct answer is true

6 0
3 years ago
Read 2 more answers
Solve the equation 6w2 – 7w – 20 = 0.
azamat

For this case we have the following quadratic equation:

6w ^ 2-7w-20 = 0

Where:

a = 6\\b = -7\\c = -20

Its roots will be given by:

w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}

The roots are:

w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}

Answer:

w_ {1} = \frac {5} {2}\\w_ {2} = - \frac {4} {3}

7 0
3 years ago
Read 2 more answers
One bottle of ongo pain medicine contains 60 tablets. How many tablets are contained in 3 3/4 bottle
Snowcat [4.5K]

answer:

600 tablets in 33/4

Step-by-step explanation:

60 =1bottle

33/4 =8.25 =8 bottles and1/4

60*8=480

480/4=120

120+480=600

5 0
4 years ago
10 in<br> Given the figure. Find AC.
rjkz [21]

Answer:

if its an arc and center angle is given it could be double the size. IF it is a triangle measure you would use Pythagoras for triangle and trig for given angle, if two triangles are shown and they are scale of each other alternative measures given divide into each measure by the correct line and check this with the matching angles. when found as a division this is the ratio so then you just multiply to find the larger measure but divide to find the smaller measure. AC could also be a junction or vector, if its a type of vector then you just follow the arrows and count how many arrows fit the line pick a direction and ie) if its x2 a then you show a+a.

Step-by-step explanation:

5 0
3 years ago
Choose the abbreviation of the postulate or theorem that supports the conclusion that WAS NOT. Given: A = O, W = N, SW = TN.
BartSMP [9]
The answer is ASA. 
Given that ∠A = ∠O, ∠W = ∠N, SW = TN, this shows that the two angles (∠A and ∠W) and the included side SW of the first triangle are equal to the two angles (∠O and ∠N) and the included side TN of the second triangle. This means that third angles ∠S and ∠T are also equal. Therefore, the two triangles ΔWAS and ΔNOT are congruent based from the ASA Postulate.
4 0
3 years ago
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