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Gekata [30.6K]
3 years ago
15

Choose the abbreviation of the postulate or theorem that supports the conclusion that WAS NOT. Given: A = O, W = N, SW = TN.

Mathematics
1 answer:
BartSMP [9]3 years ago
4 0
The answer is ASA. 
Given that ∠A = ∠O, ∠W = ∠N, SW = TN, this shows that the two angles (∠A and ∠W) and the included side SW of the first triangle are equal to the two angles (∠O and ∠N) and the included side TN of the second triangle. This means that third angles ∠S and ∠T are also equal. Therefore, the two triangles ΔWAS and ΔNOT are congruent based from the ASA Postulate.
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Answer:

He would need to save $22 dollars each week to pay for the bike in 7 weeks.

Step-by-step explanation:

We can figure out how many he has saved up already by multiplying the number of weeks (12) by how much he saved each week ($8) which equals $96. Now we have to subtract $96 from $250 which equals $154. Now we need divide this amount by the remaining weeks until he wants to purchase his bike (7), so 154/7 which equals $22.

So he needs to pay 22 dollars each week to pay off the bike in seven weeks

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3 years ago
Brooklyn wants to know how many families in her neighborhood plan to attend the parade. She puts all 120 of the neighborhood add
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Answer:

The answer is: B) Yes, this is a valid inference because it took a random sample from the neighborhood.

And apart from the random sample, 40% of families agreed with her to attend the parade at least.

Step-by-step explanation:

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3 years ago
Question 10 of 10
Nuetrik [128]

Answer:

x+9=4x-4

=) x -4x = -4-9

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=) x = 13/3

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3 years ago
In simplest form 1 3/10 x 18=
Murljashka [212]

Answer:

54/10 or 27/5

8 0
2 years ago
Read 2 more answers
Q3. Consider two identical pack of cards A and B. When one card from A is taken and shuffled with the card B, the first top card
vivado [14]

Answer:

0.02

Step-by-step explanation:

Pack A and B both consisted of 52 cards. When shuffled, 51 cards in A and 53 cards in deck B. It appears that the Top card of A left with only 51 possible cards to be taken from A (since we know the Queen hadn't moved).

The two possible cases are: probability of not taking King of Hearts (from A to B), and the other were we did.

Let K= the event of taking the King of Hearts from A to B and be B_{K} the occasion being the top card of B.

P(B_{K} )=P(K)P(B_{K} |K)+P(K^{C} )P(B_{K} |K^{C} )\\

=\frac{1}{51} \frac{2}{53} +\frac{50}{51} \frac{1}{53}

=\frac{52}{2703} \\=0.02

8 0
3 years ago
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