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3 years ago

Choose the abbreviation of the postulate or theorem that supports the conclusion that WAS NOT. Given: A = O, W = N, SW = TN.

1 answer:

4 0

The answer is ASA.
Given that ∠A = ∠O, ∠W = ∠N, SW = TN, this shows that the two angles (∠A and ∠W) and the included side SW of the first triangle are equal to the two angles (∠O and ∠N) and the included side TN of the second triangle. This means that third angles ∠S and ∠T are also equal. Therefore, the two triangles ΔWAS and ΔNOT are congruent based from the ASA Postulate.

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Find the measure of CB.

mamaluj [8]

Answer:

I'm Pretty Sure Its 40.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of

In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

A line segment joining the mid-points of two sides in a triangle is parallel to the third side and equal to half its length

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = $\frac{1}{2}$ MN

∵ JL = 11 units

∴ 11 = $\frac{1}{2}$ MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = $\frac{1}{2}$ MO

∵ KL = 13 units

∴ 13 = $\frac{1}{2}$ MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = $\frac{1}{2}$ ON

∵ ON =20 units

∴ JK = $\frac{1}{2}$ (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0

3 years ago

Answer C and D please

DENIUS [597]

Answer:

C. solution:

3(3c-2) = 5(2c-1)

or, 9c-6 = 10c-5

or, -6+5 = 10c-9c

or, -1 = 1c

Hence, c = -1.

D. solution:

5(5-2a) = 4(6-a)

or, 25-10a = 24 - 4a

or, 25-24 = -4a+10a

or, 1 = 6a

or, 1/6 = a

Hence, a = 1/6.

6 0

3 years ago

Write an equation in Standard Form. A store sells t-shirts for $12 each and

Dmitrij [34]

Standard form: Ax + By = C
Equation: 12x + 15y = 120

8 0

3 years ago

Read 2 more answers

An automatic car wash takes exactly 5 minutes to wash a car. On average, 10 cars per hour arrive at the car wash. Suppose that,

77julia77 [94]

Answer:

0.9595724

Step-by-step explanation:

Time taken to wash a car (μ) = 5 minutes

Hence, Number of cars washed per hour = 60/5 = 12 cars

If 5 cars arrive, 30 minutes to closing ; it takes 25 minutes to finish up ;

If 1 more car arrives, then it takes exactly 30 minutes

Hence, there will be no one in line at closing ;

IF 0 or 1 car arrives, if more than 1 car arrives, then there will be people in line at closing.

Hence, probability of waiting in line at closing :

1 - [p(0) + p(1)]

Using poisson :

P(x) = [(e^-μ) * (μ^x)] / x!

If x = 0

P(0) = [(e^-5) * (5^0)] / 0!

P(0) = (0.0067379 * 1) / 1

P(0) = 0.0067379

X = 1

P(1) = [(e^-5) * (5^1)] / 1!

P(0) = (0.0067379 * 5) / 1

P(0) = 0.0336897

Hence,

1 - (0.0067379 + 0.0336897)

1 - 0.0404276

= 0.9595724

Hence, the probability that anyone would be in the car washing line after closing is 0.9595724

4 0

3 years ago