Answer:
Step-by-step explanation:
We have to solve the given expression,

= 
= 
= 
= 
= 
= 
= 
Answer:
True
Step-by-step explanation:
The null space of matrix is set of all solutions to matrix. The linearly independent vectors forms subset which are spanned and forms the null space. The null space of vector can be found by reducing its echelon. The non zero rows formed are the null spaces of matrix.
Answer:
<em>Solve for b. by simplifying both sides of the inequality, then isolating the variable.</em>
Inequality Form:

Interval Notation:
(
−
∞
,
)
Hope this helps :)
<em>-ilovejiminssi♡</em>
Answer:
y=|x|
Step-by-step explanation:
We know
general modulus function passes through origin as |0| is 0
And it's symmetric on both sides of y axis .
As it's not one -one function
Means
So the graph is y=|x|
You need to remember your exponent rules. I don’t know any easier way to do it. These are all the ones I can remember right now