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Naya [18.7K]
3 years ago
9

5. (9r 3 + 5r 2 + 11r) + (-2r 3 + 9r - 8r 2)

Mathematics
1 answer:
ad-work [718]3 years ago
3 0

Answer:

7r³ - 3r² + 20r

Step-by-step explanation:

(9r³ + 5r² + 11r) + (-2r³ + 9r - 8r²)

You can get rid of the parentheses since there is nothing to distribute.

9r³ + 5r² + 11r - 2r³ + 9r - 8r²

Combine like factors.

7r³ - 3r² + 20r

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i have 30 coins, all nickels, dimes and quarters, worth $4.60. there are two more dimes than quarters.. how many of each kind of
Oliga [24]

Answer:

Step-by-step explanation:

I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.

..

let quarters be x

dimes = x+2

...

dimes + quarters = x+x+2=2x+2

...

nickels = 30-(2x+2)

...

5(30-(2x+2))+10(x+2)+25x=460

5(30-2x-2)+10x+20+25x=460

150-10x-10+10x+20+25x=460

160+25x=460

-160

25x=460-160

25x=300

/25

x=300/25

x=12 ---- quarters

x+2= 12+2=14 dimes

30-(2x+2)=4 nickels

...

check

4*5+14*10+12*25=20+140+300=460

4 0
2 years ago
Find the length of the missing leg.
quester [9]

Answer:

Step-by-step explanation:

using formula

a^2+b^2=c^2

x^2+4^2=8^2

x^2+16=64

x^2=64-16

x=\sqrt{48} cm

3 0
3 years ago
Read 2 more answers
The expression sin 57° is equal to
ValentinkaMS [17]

Answer:

cos(33^{\circ})

Step-by-step explanation:

Given

sin(57^{\circ})

Required

Determine an equivalent expression

In trigonometry:

sin(\theta)= cos(90^{\circ} - \theta)

In sin(57^{\circ})

\theta=57^{\circ}

Substitute 57^{\circ} for \theta

in sin(\theta)= cos(90^{\circ} - \theta)

sin(57^{\circ})= cos(90^{\circ} - 57^{\circ})

sin(57^{\circ})= cos(33^{\circ})

Hence, the equivalent expression is: cos(33^{\circ})

5 0
3 years ago
Which function represents by the table
andreev551 [17]
F(x)= 4x this is because everything is times 4
3 0
2 years ago
Choose whether it's always, sometimes, never 
Keith_Richards [23]

Answer: An integer added to an integer is an integer, this statement is always true. A polynomial subtracted from a polynomial is a polynomial, this statement is always true. A polynomial divided by a polynomial is a polynomial, this statement is sometimes true. A polynomial multiplied by a polynomial is a polynomial, this statement is always true.

Explanation:

1)

The closure property of integer states that the addition, subtraction and multiplication is integers is always an integer.

If a\in Z\text{ and }b\in Z, then a+b\in Z.

Therefore, an integer added to an integer is an integer, this statement is always true.

2)

A polynomial is in the form of,

p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0

Where a_n,a_{n-1},...,a_1,a_0 are constant coefficient.

When we subtract the two polynomial then the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3)

If a polynomial divided by a polynomial  then it may or may not be a polynomial.

If the degree of numerator polynomial is higher than the degree of denominator polynomial then it may be a polynomial.

For example:

f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2

Then \frac{f(x)}{g(x)}=x^2+5, which a polynomial.

If the degree of numerator polynomial is less than the degree of denominator polynomial then it is a rational function.

For example:

f(x)=x^2-2x+5x-10 \text{ and } g(x)=x-2

Then \frac{g(x)}{f(x)}=\frac{1}{x^2+5}, which a not a polynomial.

Therefore, a polynomial divided by a polynomial is a polynomial, this statement is sometimes true.

4)

As we know a polynomial is in the form of,

p(x)=a_nx^n+a_{n-1}x^{x-1}+...+a_1x+a_0

Where a_n,a_{n-1},...,a_1,a_0 are constant coefficient.

When we multiply the two polynomial, the degree of the resultand function is addition of degree of both polyminals and the resultant is also a polynomial form.

Therefore, a polynomial subtracted from a polynomial is a polynomial, this statement is always true.

3 0
3 years ago
Read 2 more answers
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