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valentina_108 [34]
3 years ago
11

24. Write 2 rational numbers between--and44​

Mathematics
1 answer:
Len [333]3 years ago
6 0

Answer:

5 and 6 are rational numbers between 4 and 44

Step-by-step explanation:

The formatting is a little weird, so I'm not sure if your asking for 2 numbers between 4 and 44, or 4 and 4

*if it is 4 and 4 then clearly it's a trick question!

I'm going to assume the first option, because the second option is impossible

5 and 6 are rational numbers between 4 and 44

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2 years ago
The table displays the number of students in each grade at Richmond High School who will or will not be attending the amusement
Pani-rosa [81]

Answer:

P( eleventh\: \: |\: \: FT)=  0.2453 \\\\P( eleventh\: \: |\: \: FT)=  24.53\% \\\\

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

P(eleventh\:  and \: FT) = \frac{13}{92}  \\\\P(eleventh \:  and \: FT) = 0.1413

Where P(FT) is the probability of students who will be going to field trip

P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\

So the required probability is

P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)=  0.2453 \\\\P( eleventh\: \: |\: \: FT)=  24.53\% \\\\

6 0
3 years ago
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