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frutty [35]
3 years ago
15

Find the value of x in the given right triangle

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0
You do the sin function on a calculator
Sin(62)=x/12
Your answer is x=10.60
vazorg [7]3 years ago
3 0

Answer:

10.6

Step-by-step explanation:

sin theta = opposite side/ hypotenuse

sin 62 = x/12

Multiply each side by 12

12 sin 62 =x

10.59537111 =x

Rounding to the nearest tenth

10.6 =x

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Viktor [21]

Answer:

Step-by-step explanation:

Rate of change= slope/gradient (Constant of proportionality, slope, unit rate)

7 0
3 years ago
What is the length of the third side of the window frame below? (Figure is not drawn to scale.) A picture of a right triangular
mina [271]
By the Pythagorean Theorem,  the longest side of a right triangle squared is equal to the sum of the squared sides...

h^2=x^2+y^2, where h=hypontenuse, and x and y are the side lengths...

87^2=w^2+63^2

w^2=87^2-63^2

w^2=3600

w=√3600

w=60 in

So the base of the frame is 60 inches wide.
8 0
4 years ago
Read 2 more answers
Find the slope and y-intercept of the following linear equation. Express the y-intercept as a coordinate pair y = 7x
strojnjashka [21]

Answer:

slope: 7

y intercept (0 , 0)

Step-by-step explanation:

y = 7x

equation of line: y = mx + b      m: slope     b: y intercept

slope = 7

y intercept: 0    (0 , 0)

6 0
4 years ago
1.x-7=20<br><br>2.3x+6=12x-21​
dusya [7]

Answer:

1. x=27

2. x=3

Step-by-step explanation:

<h3>the first one </h3>

let's solve your equation step-by-step.

x−7=20

Step 1: Add 7 to both sides.

x−7+7=20+7

<h3>the second one </h3>

Let's solve your equation step-by-step.

3x+6=12x−21

Step 1: Subtract 12x from both sides.

3x+6−12x=12x−21−12x

−9x+6=−21

Step 2: Subtract 6 from both sides.

−9x+6−6=−21−6

−9x=−27

Step 3: Divide both sides by -9.

−9x/−9=−27/−9

<h3 />
8 0
3 years ago
X-4y=28 2x+y=2 Elimination
makvit [3.9K]

\left\{\begin{array}{ccc}x-4y=28\\2x+y=2&\text{multiply both sides by 4}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x-4y=28\\8x+4y=8\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad9x=36\qquad\text{divide both sides by 9}\\.\qquad\boxed{x=4}\\\\\text{Put the value of x to the second equation:}\\\\2(4)+y=2\\8+y=2\qquad\text{subtract 8 from both sides}\\\boxed{y=-6}\\\\Answer:\ \boxed{x=4\ and\ y=-6\to(4,\ -6)}

3 0
3 years ago
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