Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.
Hope I could help.
Answer:
0
Step-by-step explanation:
f(x) = 2/5(6 - x)²
f(6) = 2/5[6 - (6)]²
f(6) = 2/5(0)²
f(6) = 0
Answer:
its the second one lol its just asking you to pick the one less than a and a is 0.11 so it would be 0.0019
Step-by-step explanation:
Answer:
<h2>A
pproximately 4824 games </h2>
Step-by-step explanation:
Given that the sales made are 4,567 ,5430, 3998, 5,220,and 4,906
the average is (4567+5430+3998+5220+4906)/5
=24121/5
=4824.2
in the month of august let the sales be x
average= (4567+5430+3998+5220+4906+x)/6
the average for march to july is 4824.2
4824.2= (4567+5430+3998+5220+4906+x)/6
24121+x=4824.2*6
24121+x=28945.2
x=28945.2-24121
x=4824.2
approximately 4824 games
Answer:
X=22
Step-by-step explanation:
All the angles in every triangle must add up to 180 so we can subtract 23 and 135 from 180 to get 22.
