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Ivanshal [37]
3 years ago
11

I need help solving algebra equations to teach my kid. D-4=12.4 D=?

Mathematics
2 answers:
Andreyy893 years ago
7 0

Answer: d=16.4

Step-by-step explanation:

Step 1) Add 4 to both sides: d-4+4=12.4+4

d=16.4

Luda [366]3 years ago
4 0

Answer: D=16 please give brainliest

Step-by-step explanation:

D-4=12

first add +4 to both sides to reverse it

D=16 and to make sure its right

lets substutie for D

16-4=12

12=12

correct

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2 times the difference between 49.5 and 37.5
Xelga [282]
I belive the answer would be....
49.5-37.5=12
2•12=24
6 0
3 years ago
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A publisher reports that 344% of their readers own a particular make of car. A marketing executive wants to test the claim that
inysia [295]

Answer:

No, there is not enough evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

We are given that a publisher reports that 34% of their readers own a particular make of car. A random sample of 220 found that 30% of the readers owned a particular make of car.

And, a marketing executive wants to test the claim that the percentage is actually different from the reported percentage, i.e;

Null Hypothesis, H_0 : p = 0.34 {means that the percentage of readers who own a particular make of car is same as reported 34%}

Alternate Hypothesis, H_1 : p \neq 0.34 {means that the percentage of readers who own a particular make of car is different from the reported 34%}

The test statistics we will use here is;

                T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } } ~ N(0,1)

where, p = actual % of readers who own a particular make of car = 0.34

            \hat p = percentage of readers who own a particular make of car in a

                  sample of 220 = 0.30

            n = sample size = 220

So, Test statistics = \frac{0.30 -0.34}{\sqrt{\frac{0.30(1- 0.30)}{220} } }

                             = -1.30

Now, at 0.02 significance level, the z table gives critical value of -2.3263 to 2.3263. Since our test statistics lie in the range of critical values which means it doesn't lie in the rejection region, so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the actual percentage of readers who own a particular make of car is same as reported percentage and the executive's claim that it is different is not supported.

3 0
3 years ago
A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la
SOVA2 [1]

Answer:

8\pi\text{ square cm}

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

S=2\pi rh

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

4^2 = (2r)^2 + h^2   ( see in the below diagram ),

16 = 4r^2 + h^2

16 - 4r^2 = h^2

\implies h=\sqrt{16-4r^2}

Thus, the surface area of the cylinder,

S=2\pi r(\sqrt{16-4r^2})

Differentiating with respect to r,

\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})

=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})

=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})

Again differentiating with respect to r,

\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})

For maximum or minimum,

\frac{dS}{dt}=0

2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0

-8r^2 + 16 = 0

8r^2 = 16

r^2 = 2

\implies r = \sqrt{2}

Since, for r = √2,

\frac{d^2S}{dt^2}=negative

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

S = 2\pi (\sqrt{2})(\sqrt{16-8})

=2\pi (\sqrt{2})(\sqrt{8})

=2\pi \sqrt{16}

=8\pi\text{ square cm}

4 0
3 years ago
Which values are outliers? 6. 1, 3. 9, 6. 4, 10. 6, 4. 4, 4. 5, 1. 6, 11. 2, 0. 8, 3. 9, 6. 5 Select Outlier or Not Outlier for
Kisachek [45]

Answer:

<em>10 and 11</em>

Step-by-step explanation:

  1. An outlier is a number that is much larger or smaller than the general populous of numbers. For example, if there was a dot plot with dots clustered at 2, 3, and 5, but there was one or two dots around 10, then 10 would be considered an outlier.
  2. Let's put the numbers in order to see easier which numbers are outliers. I will not copy down repeating numbers.
  3. 0, 1, 2, 3, 4, 5, 6, 10, 11.
  4. 10 and 11 are isolated.

If I am incorrect in my reasoning, please let me know so that I can plan better for my future answers. Have an amazing day.

8 0
3 years ago
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