Find the minimum, first quartile, median, third quartile, and maximum of each data set, 12, 10, 11, 7, 9, 10, 5
Sliva [168]
To find the median:
Least to greatest order:
5, 7, 9, 10, 10, 11, 12
10 is the number in the middle. Therefore the median is 10
A. True. Plug in x = 0 and it leads to y = 1.
B. False. The function is undefined when cos(x) = 0 which is when x = n*pi/2 for any odd integer n. So x = pi/2, x = 3pi/2, x = 5pi/2, etc are not allowed as input values.
C. True. This is one of the infinitely many vertical asymptotes, which result from to the fact that x = pi/2 is not allowed in the domain.
D. False. Sine can be equal to zero. The only thing we need to make sure that is nonzero is the cosine value, since secant = 1/cosine
E. False. Choice B talks about values excluded from the domain.
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<h3>In summary, the answers are Choice A and Choice C</h3>
She used the factor 3, she multiplied 5 by 3 and 7 by 3
main answer is just 3
Answer:
Just took the test the answer is C
Step-by-step explanation:
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Answer:
The cost of one brownie is $0.75
Step-by-step explanation:
The given parameters are;
The number of pizza's Marcel bought = 4 pieces
The number of brownies Marcel bought = 2 brownies
The amount Marcel paid = $18.50
The number of pizza's Morgan bought = 3 pieces
The number of brownies Morgan bought = 2 brownies
The amount Morgan paid = $14.25
Let x represent the cost of a pizza and y represent the cost of a brownie, we have;
4·x + 2·y = $18.50...(1)
3·x + 2·y = $14.25...(2)
Subtracting equation (1) from equation (2) gives;
4·x + 2·y - (3·x + 2·y) = $18.50 - $14.25 = $4.25
4·x - 3·x + 2·y - 2·y = $4.25
x = $4.25
The cost of a pizza = x = $4.25
4·x + 2·y = $18.50
2·y = $18.50 - 4·x = $18.50 - 4×$4.25 = $1.5
y = $1.5/2 = $0.75
y = $0.75
The cost of a brownie = $0.75
