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3 years ago

I need help finding the area

Mathematics

1 answer:

Kitty [74]3 years ago

4 0

Make drawing (see attachment)
do big rectangle minus triangle

big rectangle area=lenght timess width=22 times 33=726 square feet
triangle=1/2 times base times height=1/2 times 9 times 10=45 square feet

rectangle-triangle=726-45=681 square feet

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Each morning, Hungry Harry eats some eggs. On any given morning, the number of eggs he eats is equally likely to be 1, 2, 3, 4,

mamaluj [8]

Answer:

Mean = 35

Variance = 291.7

Step-by-step explanation:

Data provided in the question:

X : 1, 2, 3, 4, 5, 6

All the data are independent

Thus,

The mean for this case will be given as:

Mean, E[X] = $\frac{\textup{Sum of all the observations}}{\textup{Total number of observations}}$

E[X] = $\frac{\textup{1+2+3+4+5+6}}{\textup{6}}$

E[X] = 3.5

For 10 days, Mean = 3.5 × 10 = 35

And,

variance = E[X²] - ( E[X] )²

Now, for this case of independent value,

E[X²] = $\frac{1^2+2^2+3^2+4^2+5^2+6^2}{\textup{6}}$

E[X²] = $\frac{1+4+9+16+25+36}{\textup{6}}$

E[X²] = $\frac{91}{\textup{6}}$

E[X²] = 15.167

Therefore,

variance = E[X²] - ( E[X] )²

variance = 15.167 - 3.5²

Variance = 2.917

For 10 days = Variance × Days²

= 2.917 × 10²

= 291.7

3 0

3 years ago

3-6n+3n=-3+4-4n can somebody help me?

ElenaW [278]

Anwser : n = -2
Combine Like Terms
Add 4n to both sides
Subtract 3 from both sides
A = n= -2

8 0

3 years ago

What are the coordinates of the point on the directed line segment from (6, -10) to

sveta [45]

Answer:

There are 2

(6 2/5, -6 2/5)

(8 3/5, 4 2/5)

Step-by-step explanation:

8 0

3 years ago

ANSWER THIS QUESTION FOR BRAINLEST AND 10 POINTS

ivolga24 [154]

Answer:

I beleive that the answer is (1,2)

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

If x = a cosθ and y = b sinθ , find second derivative

Olin [163]

I'm guessing the second derivative is for <em>y</em> with respect to <em>x</em>, i.e.

$\dfrac{\mathrm d^2y}{\mathrm dx^2}$

Compute the first derivative. By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta$

$x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta$

Now compute the second derivative. Notice that $\frac{\mathrm dy}{\mathrm dx}$ is a function of $\theta$ ; so denote it by $f(\theta)$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}$

By the chain rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta$

and so the second derivative is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta$

4 0

3 years ago