A bearing of 34° corresponds to corresponding angle of θ=90-34=56° The (x,y) values for the position of the ship after completing its first heading are: x=(10.4cos 56) y=(10.4sin56)
The trigonometric angle for θ=90-90=0 The (x,y) values for the postion of the ship after completing the second bearing is: x=(10.4 cos56)+(4.6cos0)≈10.4 mi y=(10.4sin56)+(4.6sin0)≈8.6mi
the distance from the port will therefore be: d=√(10.4²+8.6²)≈13.5 miles
It trigonometric angles is: θ=arctan(y/x) θ=arctan(8.6/10.4) θ≈39.6° Thus the bearing angle is: 90-39.6=50.4°
