<span>Instead of thinking about reliability think of failure. 99.999% reliability =0.00001 chance of failure. And 95% reliability =0.05 chance of failure. Assuming failures are independent (they probably are not) the chance of n servers failing is (0.05)n Find n such that (0.05)n=(0.00001) now do it for (0.14)n=(0.00001)</span>
Answer:
All three are yes
Step-by-step explanation:
4. yes
5.yes
6.yes
It’s doesn’t satisfy the equation
Answer:
5/4
Step-by-step explanation:
since you cannot put 2.5 : 2 into a fraction you double both numbers and you get 5 : 4 and this as a fraction is 5/4
hope this helps :)
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
