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3 years ago

What is the answer???

Mathematics

1 answer:

11111nata11111 [884]3 years ago

8 0

Answer:

Check the attached picture, the answer with working is shown :)

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4.2% of what number is 58.8?

katen-ka-za [31]

Answer:

1400

Step-by-step explanation:

3 0

3 years ago

The O! Natural Company is trying to get schools in the state to sell their juice product.

Karolina [17]

Answer:

For a. divide 125 by 300 then multiply by 100

The answer for a. is 41.66%

For b. convert percentage to decimal divide by 100 then multiply 0.15 by 2.25 to get 0.3375‬. Round it off to 0.34 and subtract that from 2.25 to get

The answer for b. is $1.91

For c. you have to figure out the difference first. 2.50 minus 2.00 is 0.50

So then what percent of 2.00 is 0.50

Divide 2.00 by 0.50 to get 4.

The answer for c. is 4%

Honestly this was kinda rushed because I'm in the middle of a quiz so yea hope this helps you.

From yours truly to you,

<em>Que</em>.

8 0

3 years ago

Starting salaries of 90 college graduates who have taken a statistics course have a mean of $43,993 and a standard deviation of

inysia [295]

Answer:

a) E = 2482.90

b) 99% Confidence interval: (41510.1,46475.9)

Step-by-step explanation:

We are given the following in the question:

Sample mean, $\bar{x}$ =$43,993

Sample size, n = 90

Alpha, α = 0.051

Sample standard deviation, s = $9,144

a) The margin of error

Formula:

$z_{critical}\text{ at}~\alpha_{0.01} = 2.576$

$E =z_{critical}\times \displaystyle\frac{s}{\sqrt{n}}\\\\E = 2.576\times \frac{9144}{\sqrt{90}}\\\\E = 2482.90$

b) 99% Confidence interval:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$43993 \pm 2482.90 = (41510.1,46475.9)$

3 0

3 years ago

Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}

miskamm [114]

Answer:

$-3+i\sqrt{3} , 1+\sqrt{3}$

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

$\alpha = x+iy\\\beta = x-iy$

since they are conjugates

$\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}$

$\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}$

Imaginary part of the above =0

i.e. $\sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1$

So the value of alpha = $-3+i\sqrt{3} , 1+\sqrt{3}$

3 0

3 years ago

Parabola,,Could you help me please??

stepan [7]

Answer:

$\large \boxed{\sf \bf \sqrt{\dfrac{10}{3}}}$

Dimension of the rectangle is

$2\times\sqrt{\dfrac{10}{3}}\\ \\10-\dfrac{10}{3}=\dfrac{20}{3}$

Step-by-step explanation:

Hello,

$\text{The area is }2x(1-x^2) \\ \\\text{The derivative is }2(10-x^2)+2x(-2x)=2(10-3x^2)\\\\\text{The derivative is }0\text{ for} 10-3x^2=0 \\\text{so for } x=\sqrt{\dfrac{10}{3}}$

Thanks

5 0

4 years ago