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3 years ago

Help please variations questions

Mathematics

1 answer:

vovikov84 [41]3 years ago

5 0

Answer:

Step-by-step explanation:

first graph

<h2>height=constant* width ( direct variation describes a linear relation between 2 variable )</h2>

6=8x ⇒ x=6/8=0.75

h=0.75w

<h2>constant is 0.75</h2>

second graph:

<h2>height=constant/width ( inverse variation)</h2>

15=x/4 ⇒x=4*15 ⇒x=60

<h2>constant=60</h2>

For two quantities with inverse variation, as one quantity increases, the other quantity decreases. k(constant)=xy

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If Y= 9, is the inequality true or false? Y + 3 < 12

Serjik [45]

Answer:

False

Step-by-step explanation:

To solve this problem, plug in the value for Y, 9, into the inequality.

9 + 3 < 12

Now, solve the inequality. Evaluating 9 + 3, the equation becomes:

12 < 12

12 is not less than 12 (12 = 12), therefore the answer is false.

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3 years ago

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Answer:

1250000

Step-by-step explanation:

Let number of the total number of shoes sold be 'y'

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3 years ago

Taft CLB Algebra 2 Unit 1: Systems of Linear Equations and Inequalities 2020-2021 / 3 of 13

Tju [1.3M]

Answer:

$B + G \leq 15$

$6B + 10G \geq 90$

Step-by-step explanation:

Given

Represent Babysitting with B

Represent Gas Station with G

Total workhours = At most 15

Earnings = At least $90

First, we need to represent the work hours as inequality

B + G = At most 15

At most 15 means less than or equal to 15.

So, we have:

$B + G \leq 15$

Next, we represent the earnings as inequality.

6 hours of babysitting is: 6B

10 hours at gas station is: 10G

So:

6B + 10G is at least 90

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So, we have:

$6B + 10G \geq 90$

8 0

2 years ago

Please help me with this question!

gavmur [86]

First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway thus

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{first sol'n}&11&x&11x\\
\textit{second sol'n}&4&0.55&2.20\\
------&-----&-------&-------\\
mixture&y&0.77&0.77y
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
11+4=y\implies 15=\boxed{y}\\
11x+2.2=0.77y\\
----------\\
11x+2.2=0.77\cdot \boxed{15}
\end{cases}$

solve for "x"

6 0

3 years ago